The sum of four consecutive even numbers is 44. Find the highest of them.

Let the four consecutive even numbers be represented as \( x, x+2, x+4, \) and \( x+6 \).

The sum of these four numbers is given as:

\[
x + (x + 2) + (x + 4) + (x + 6) = 44
\]

Simplifying the left-hand side:

\[
4x + 12 = 44
\]

Now, subtract 12 from both sides:

\[
4x = 44 - 12
\]

\[
4x = 32
\]

Now, divide by 4:

\[
x = 8
\]

So, the four consecutive even numbers are \( 8, 10, 12, \) and \( 14 \). 

The highest number is **14**.

Would you like more details or have any other questions?

Here are 5 related questions:
1. What is the sum of four consecutive odd numbers if the highest is 15?
2. How would the equation change if the sum were 64 instead of 44?
3. What would be the four consecutive numbers if they were odd and their sum was 44?
4. If three consecutive even numbers sum to 36, what is the largest number?
5. How would the solution differ if we were working with consecutive multiples of 3?

**Tip:** When dealing with consecutive even or odd numbers, always remember their difference is 2.

The sum of four consecutive even numbers is 44. Find the highest of them.

Discover how to solve the problem of finding the highest of four consecutive even numbers that add up to 44. This algebra problem is perfect for students in Grades 6-8, covering key concepts like arithmetic sequences and equation solving.

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