Math Problem Statement
Find the sum of the first 7 terms of the following sequence. Round to the nearest hundredth if necessary. 6, comma, minus, 10, comma, start fraction, 50, divided by, 3, end fraction, comma, dot dot dot 6,−10, 3 50 ,... Sum of a finite geometric series: Sum of a finite geometric series: S, start subscript, n, end subscript, equals, start fraction, a, start subscript, 1, end subscript, minus, a, start subscript, 1, end subscript, r, to the power n , divided by, 1, minus, r, end fraction S n
1−r a 1 −a 1 r n
Solution
The sequence you provided is a geometric sequence:
Step 1: Identify the first term and common ratio.
- First term
- To find the common ratio , divide the second term by the first term:
Step 2: Use the formula for the sum of the first terms of a geometric series:
The sum of the first terms of a geometric series is given by:
For this sequence, we need to find the sum of the first 7 terms, so , , and .
Step 3: Calculate :
Step 4: Compute powers and simplify.
-
Calculate .
- This gives .
-
Now, substitute this into the sum formula:
Simplifying the denominator .
Simplifying:
Final Answer:
The sum of the first 7 terms is approximately 82.7.
Would you like to go over any part of the calculation in more detail or explore further examples?
Additional Questions:
- How does the common ratio affect the sum of a geometric series?
- Can you find the sum of the first 10 terms of a different geometric sequence?
- How do you determine whether a geometric series converges or diverges?
- What happens to the sum of a geometric series when the common ratio is between -1 and 1?
- How do you calculate the infinite sum of a convergent geometric series?
Tip: Always check the common ratio to ensure that it’s not equal to 1, as the sum formula won't work when .
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Math Problem Analysis
Mathematical Concepts
Geometric Sequences
Series
Summation of Geometric Series
Formulas
Sum of a geometric series: S_n = (a_1(1 - r^n)) / (1 - r)
Theorems
Sum of the first n terms of a geometric series
Suitable Grade Level
Grades 9-12