Math Problem Statement

Find the sum of the first 7 terms of the following sequence. Round to the nearest hundredth if necessary. 6, comma, minus, 10, comma, start fraction, 50, divided by, 3, end fraction, comma, dot dot dot 6,−10, 3 50 ​ ,... Sum of a finite geometric series: Sum of a finite geometric series: S, start subscript, n, end subscript, equals, start fraction, a, start subscript, 1, end subscript, minus, a, start subscript, 1, end subscript, r, to the power n , divided by, 1, minus, r, end fraction S n ​

1−r a 1 ​ −a 1 ​ r n

Solution

The sequence you provided is a geometric sequence:

6,10,503,6, -10, \frac{50}{3}, \dots

Step 1: Identify the first term and common ratio.

  • First term a1=6a_1 = 6
  • To find the common ratio rr, divide the second term by the first term:

r=106=53r = \frac{-10}{6} = -\frac{5}{3}

Step 2: Use the formula for the sum of the first nn terms of a geometric series:

The sum of the first nn terms of a geometric series is given by:

Sn=a1(1rn)1rS_n = \frac{a_1(1 - r^n)}{1 - r}

For this sequence, we need to find the sum of the first 7 terms, so n=7n = 7, a1=6a_1 = 6, and r=53r = -\frac{5}{3}.

Step 3: Calculate S7S_7:

S7=6(1(53)7)1(53)S_7 = \frac{6 \left( 1 - \left( -\frac{5}{3} \right)^7 \right)}{1 - \left( -\frac{5}{3} \right)}

Step 4: Compute powers and simplify.

  1. Calculate (53)7\left( -\frac{5}{3} \right)^7.

    • This gives (53)7=781252187\left( -\frac{5}{3} \right)^7 = -\frac{78125}{2187}.
  2. Now, substitute this into the sum formula:

S7=6(1(781252187))1+53S_7 = \frac{6 \left( 1 - \left( -\frac{78125}{2187} \right) \right)}{1 + \frac{5}{3}}

Simplifying the denominator 1+53=831 + \frac{5}{3} = \frac{8}{3}.

S7=6(1+781252187)83=6(2187+781252187)83S_7 = \frac{6 \left( 1 + \frac{78125}{2187} \right)}{\frac{8}{3}} = \frac{6 \left( \frac{2187 + 78125}{2187} \right)}{\frac{8}{3}}

Simplifying:

S7=6×80312218783=6×803122187×38S_7 = \frac{6 \times \frac{80312}{2187}}{\frac{8}{3}} = \frac{6 \times 80312}{2187} \times \frac{3}{8}

S7=6×80312×32187×8=14456161749682.7S_7 = \frac{6 \times 80312 \times 3}{2187 \times 8} = \frac{1445616}{17496} \approx 82.7

Final Answer:

The sum of the first 7 terms is approximately 82.7.

Would you like to go over any part of the calculation in more detail or explore further examples?


Additional Questions:

  1. How does the common ratio affect the sum of a geometric series?
  2. Can you find the sum of the first 10 terms of a different geometric sequence?
  3. How do you determine whether a geometric series converges or diverges?
  4. What happens to the sum of a geometric series when the common ratio is between -1 and 1?
  5. How do you calculate the infinite sum of a convergent geometric series?

Tip: Always check the common ratio rr to ensure that it’s not equal to 1, as the sum formula won't work when r=1r = 1.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Series
Summation of Geometric Series

Formulas

Sum of a geometric series: S_n = (a_1(1 - r^n)) / (1 - r)

Theorems

Sum of the first n terms of a geometric series

Suitable Grade Level

Grades 9-12