Math Problem Statement

Find the sum of the first 50 terms, (4,4,4,4,4,...) using formula Sn = A1 (1-r^n) / 1-r

Solution

The sequence you provided is 4,4,4,4,4, 4, 4, 4, \dots, which is a constant sequence. This means it's not a geometric progression, but a constant arithmetic sequence. However, the formula you mentioned:

Sn=A11rn1rS_n = A_1 \frac{1 - r^n}{1 - r}

is for the sum of a geometric series, which applies when the common ratio r1r \neq 1. For this constant sequence, the ratio r=1r = 1, and the sum formula would not apply directly.

Since each term in the sequence is 44, we can instead calculate the sum using a simple formula for the sum of an arithmetic sequence where each term is the same:

Sn=n×A1S_n = n \times A_1

Where:

  • n=50n = 50 (the number of terms),
  • A1=4A_1 = 4 (the value of each term).

Thus, the sum of the first 50 terms is:

S50=50×4=200S_{50} = 50 \times 4 = 200

Final Answer:

The sum of the first 50 terms is 200200.

Would you like further details or explanations?

Here are 5 related questions to deepen your understanding:

  1. How would the formula for a geometric series apply if the ratio r1r \neq 1?
  2. What is the formula for the sum of the first nn terms of an arithmetic sequence?
  3. How does the sum of an infinite geometric series differ from a finite one?
  4. What happens to the sum of terms when the common ratio r>1r > 1 in a geometric series?
  5. How can you determine if a sequence is arithmetic or geometric based on its terms?

Tip: When working with constant sequences, remember that the sum is simply the value of the term multiplied by the number of terms!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Summation of Series

Formulas

Sn = A1 (1 - r^n) / (1 - r) for geometric sequences
Sn = n * A1 for constant sequences

Theorems

Summation formula for arithmetic sequences
Summation of constant sequences

Suitable Grade Level

Grades 6-8