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The problem asks for the result of subtracting the second equation from the first. Let's perform the subtraction step by step.

We have the following two equations:

1. \( 8x - 4y = -4 \)
2. \( -3x + 4y = 5 \)

### Step 1: Subtract the second equation from the first.
This means we subtract the left-hand side (LHS) and right-hand side (RHS) of the second equation from the corresponding sides of the first equation.

\[
(8x - 4y) - (-3x + 4y) = (-4) - (5)
\]

### Step 2: Simplify both sides.

- Left-hand side:
\[
8x - 4y - (-3x + 4y) = 8x - 4y + 3x - 4y = (8x + 3x) + (-4y - 4y) = 11x - 8y
\]

- Right-hand side:
\[
-4 - 5 = -9
\]

### Step 3: Write the resulting equation.

\[
11x - 8y = -9
\]

Thus, the result of subtracting the second equation from the first is:
\[
11x - 8y = -9
\]

Would you like more details or have any questions?

Here are five related questions to deepen your understanding:
1. How do you solve the system of equations after subtracting them?
2. What happens when you add the two equations instead of subtracting?
3. How can you eliminate variables using substitution in this system of equations?
4. What is the importance of organizing terms when performing subtraction on equations?
5. How would you graph these two linear equations and find the intersection point?

**Tip:** When subtracting equations, be mindful of distributing the negative sign across all terms in the equation you're subtracting.

What is the result of subtracting the second equation from the first? Given equations: 8x - 4y = -4 and -3x + 4y = 5.

Learn how to subtract two linear equations, 8x - 4y = -4 and -3x + 4y = 5, step by step. Understand the key algebraic concepts and techniques for solving the result after subtraction. Suitable for students in Grades 8-10.

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