What is the result of subtracting the second equation from the first?
 
\[\begin{aligned}
8x-4y &= -4 \\\\
-3x+4y &= 5
\end{aligned}\]

To subtract the second equation from the first, we perform term-by-term subtraction. The two equations are:

\[
\text{1st:} \quad 8x - 4y = -4
\]
\[
\text{2nd:} \quad -3x + 4y = 5
\]

Now, subtract the second equation from the first. This is done by subtracting the left-hand side (LHS) of the second equation from the LHS of the first equation, and similarly for the right-hand side (RHS):

\[
(8x - 4y) - (-3x + 4y) = (-4) - (5)
\]

Simplify both sides:

\[
8x - 4y + 3x - 4y = -4 - 5
\]

Combine like terms:

\[
(8x + 3x) - (4y + 4y) = -4 - 5
\]
\[
11x - 8y = -9
\]

Thus, the result of subtracting the second equation from the first is:

\[
11x - 8y = -9
\]

Do you have any questions or would you like further details?

Here are 5 related questions for further exploration:
1. How do you solve the system of equations using substitution?
2. Can you solve this system using the addition (elimination) method?
3. What happens if we subtract the first equation from the second?
4. How would graphing these equations help in finding the solution?
5. How does multiplying an equation by a constant affect the system?

**Tip:** When subtracting equations in a system, always align similar terms (e.g., \(x\)-terms with \(x\)-terms) to avoid mistakes.

What is the result of subtracting the second equation from the first?

\[
8x - 4y = -4
\]
\[
-3x + 4y = 5
\]

Explore the method of subtracting two linear equations: 8x - 4y = -4 and -3x + 4y = 5. Learn how to solve this system using elimination by subtracting equations term by term, resulting in 11x - 8y = -9. Suitable for students in Grades 8-10.

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