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We are asked to subtract the second equation from the first. The two given equations are:

1. \( -3x + 2y = 7 \)
2. \( -3x - 2y = 4 \)

Now, subtract the second equation from the first. To do this, subtract both the left-hand and right-hand sides of the equations.

\[
(-3x + 2y) - (-3x - 2y) = 7 - 4
\]

Simplifying the left-hand side:

\[
-3x + 2y + 3x + 2y = 7 - 4
\]

Notice that \( -3x \) and \( +3x \) cancel each other out:

\[
2y + 2y = 3
\]

This simplifies further to:

\[
4y = 3
\]

So, the result of subtracting the second equation from the first is:

\[
4y = 3
\]

Would you like more details or have any questions?

Here are five related questions to explore:
1. How do you solve for \( y \) in \( 4y = 3 \)?
2. What happens when you subtract two equations with more complex coefficients?
3. Can this method be applied to systems of three or more equations?
4. What is the geometric interpretation of subtracting equations in a system?
5. How does adding instead of subtracting equations change the solution?

**Tip:** When subtracting equations, ensure to distribute the negative sign properly across all terms in the second equation.

What is the result of subtracting the second equation from the first?
-3x + 2y = 7
-3x - 2y = 4

Learn how to subtract two linear equations: -3x + 2y = 7 and -3x - 2y = 4. This step-by-step solution involves eliminating the x variable and solving for y. Ideal for students in Grades 7-10.

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