Math Problem Statement
How many grams of iron are prepared by reaction of 3.75 g of magnesium and 100.0 mL of a 1.23 M solution of iron(III) chloride?
The balanced reaction (write any coefficients of "1" explicitly) is:
Answer 1 Question 15 Mg(s) + Answer 2 Question 15 FeCl3(aq) → Answer 3 Question 15 MgCl2(aq) + Answer 4 Question 15 Fe.
Solution
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Stoichiometry
Mole Calculations
Limiting Reactants
Molar Mass
Chemical Reactions
Formulas
n = m / M (moles of magnesium)
n = Molarity × Volume (moles of iron(III) chloride)
Mole ratio (Mg to FeCl₃) comparison
n_Fe = (2/3) × n_Mg (moles of iron produced)
m_Fe = n_Fe × M_Fe (mass of iron)
Theorems
Law of Conservation of Mass
Stoichiometric Principles
Suitable Grade Level
Grades 10-12
Related Recommendation
Calculate Al2O3 Produced from 2.08 g of Al and Excess Fe2O3
Limiting Reagent and AgCl Formation in AgNO3 and FeCl3 Reaction
Percent Yield Calculation for MnO2 and HCl Reaction
Stoichiometry Problem: Moles of Iron(III) Chloride Formed
Stoichiometry: Calculate Mass of Calcium Oxide from Calcium and Oxygen