Math Problem Statement

A powder contains FeSO₄ · 7H₂O (molar mass = 278.01 g/mol), among other components. A 3.660 g sample of the powder was dissolved in HNO₃ and heated to convert all iron to Fe³⁺. The addition of NH₃ precipitated Fe₂O₃ · xH₂O, which was subsequently ignited to produce 0.472 g of Fe₂O₃. What was the mass of FeSO₄ · 7H₂O in the 3.660 g sample?

Solution

The problem asks to determine the mass of FeSO₄ · 7H₂O in a sample of 3.660 g based on the mass of Fe₂O₃ (0.472 g) obtained after a series of reactions.

Let's break down the solution step by step:

1. Chemical Reaction Involved

When FeSO₄ · 7H₂O is dissolved and treated, iron (Fe²⁺) is converted to Fe³⁺, which precipitates as Fe₂O₃ after heating. The key is to relate the amount of Fe₂O₃ produced to the original amount of FeSO₄ · 7H₂O.

  • Molar mass of Fe₂O₃: Fe2O3=2×55.85(Fe)+3×16(O)=159.7g/mol\text{Fe}_2\text{O}_3 = 2 \times 55.85 \, (\text{Fe}) + 3 \times 16 \, (\text{O}) = 159.7 \, \text{g/mol}

  • Moles of Fe₂O₃ produced: moles of Fe2O3=mass of Fe2O3molar mass of Fe2O3=0.472g159.7g/mol=0.002955mol\text{moles of Fe}_2\text{O}_3 = \frac{\text{mass of Fe}_2\text{O}_3}{\text{molar mass of Fe}_2\text{O}_3} = \frac{0.472 \, \text{g}}{159.7 \, \text{g/mol}} = 0.002955 \, \text{mol}

2. Determine Moles of Iron (Fe³⁺)

Fe₂O₃ contains two moles of Fe atoms for every mole of Fe₂O₃.

  • Moles of Fe in 0.472 g of Fe₂O₃: moles of Fe=2×0.002955mol=0.00591mol\text{moles of Fe} = 2 \times 0.002955 \, \text{mol} = 0.00591 \, \text{mol}

3. Relate to FeSO₄ · 7H₂O

Each mole of Fe in FeSO₄ · 7H₂O corresponds to one mole of FeSO₄ · 7H₂O.

  • Moles of FeSO₄ · 7H₂O: moles of FeSO₄ \cdotp 7H₂O=0.00591mol\text{moles of FeSO₄ · 7H₂O} = 0.00591 \, \text{mol}

4. Calculate the Mass of FeSO₄ · 7H₂O

Now, using the molar mass of FeSO₄ · 7H₂O (278.01 g/mol):

  • Mass of FeSO₄ · 7H₂O: mass of FeSO₄ \cdotp 7H₂O=0.00591mol×278.01g/mol=1.643g\text{mass of FeSO₄ · 7H₂O} = 0.00591 \, \text{mol} \times 278.01 \, \text{g/mol} = 1.643 \, \text{g}

Thus, the mass of FeSO₄ · 7H₂O in the 3.660 g sample is 1.643 g.


Would you like further details on any part of the calculation? Here are some additional questions to explore this problem further:

  1. How does the mass of FeSO₄ · 7H₂O compare to the total sample mass of 3.660 g?
  2. What assumptions are made when calculating the moles of iron from Fe₂O₃?
  3. How would the result change if the sample had been impure or contained other iron salts?
  4. Can you describe the reaction steps converting Fe²⁺ to Fe₂O₃?
  5. Why is NH₃ added to the reaction to precipitate Fe₂O₃?

Tip: Always double-check stoichiometric ratios when converting between compounds, especially in precipitation reactions!

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Math Problem Analysis

Mathematical Concepts

Stoichiometry
Mole Concept
Mass Calculation

Formulas

moles = mass / molar mass
mass of FeSO₄ · 7H₂O = moles × molar mass

Theorems

Law of Conservation of Mass

Suitable Grade Level

Grades 11-12 (Chemistry)