Math Problem Statement
Solution
The problem asks to determine the mass of FeSO₄ · 7H₂O in a sample of 3.660 g based on the mass of Fe₂O₃ (0.472 g) obtained after a series of reactions.
Let's break down the solution step by step:
1. Chemical Reaction Involved
When FeSO₄ · 7H₂O is dissolved and treated, iron (Fe²⁺) is converted to Fe³⁺, which precipitates as Fe₂O₃ after heating. The key is to relate the amount of Fe₂O₃ produced to the original amount of FeSO₄ · 7H₂O.
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Molar mass of Fe₂O₃:
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Moles of Fe₂O₃ produced:
2. Determine Moles of Iron (Fe³⁺)
Fe₂O₃ contains two moles of Fe atoms for every mole of Fe₂O₃.
- Moles of Fe in 0.472 g of Fe₂O₃:
3. Relate to FeSO₄ · 7H₂O
Each mole of Fe in FeSO₄ · 7H₂O corresponds to one mole of FeSO₄ · 7H₂O.
- Moles of FeSO₄ · 7H₂O:
4. Calculate the Mass of FeSO₄ · 7H₂O
Now, using the molar mass of FeSO₄ · 7H₂O (278.01 g/mol):
- Mass of FeSO₄ · 7H₂O:
Thus, the mass of FeSO₄ · 7H₂O in the 3.660 g sample is 1.643 g.
Would you like further details on any part of the calculation? Here are some additional questions to explore this problem further:
- How does the mass of FeSO₄ · 7H₂O compare to the total sample mass of 3.660 g?
- What assumptions are made when calculating the moles of iron from Fe₂O₃?
- How would the result change if the sample had been impure or contained other iron salts?
- Can you describe the reaction steps converting Fe²⁺ to Fe₂O₃?
- Why is NH₃ added to the reaction to precipitate Fe₂O₃?
Tip: Always double-check stoichiometric ratios when converting between compounds, especially in precipitation reactions!
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Math Problem Analysis
Mathematical Concepts
Stoichiometry
Mole Concept
Mass Calculation
Formulas
moles = mass / molar mass
mass of FeSO₄ · 7H₂O = moles × molar mass
Theorems
Law of Conservation of Mass
Suitable Grade Level
Grades 11-12 (Chemistry)