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To solve this problem, we need to determine the mass of calcium oxide (\(\text{CaO}\)) that can be produced from 6.17 g of calcium (\(\text{Ca}\)) and 4.11 g of oxygen (\(\text{O}_2\)) using the provided chemical reaction:

\[
2\text{Ca} + \text{O}_2 \rightarrow 2\text{CaO}
\]

### Step 1: Calculate the moles of calcium and oxygen

1. **Molar mass of calcium (\(\text{Ca}\))**: 40.08 g/mol
2. **Molar mass of oxygen gas (\(\text{O}_2\))**: \(2 \times 16.00 = 32.00\) g/mol

**Moles of calcium:**

\[
\text{Moles of Ca} = \frac{6.17 \, \text{g}}{40.08 \, \text{g/mol}} \approx 0.154 \, \text{mol}
\]

**Moles of oxygen:**

\[
\text{Moles of O}_2 = \frac{4.11 \, \text{g}}{32.00 \, \text{g/mol}} \approx 0.128 \, \text{mol}
\]

### Step 2: Determine the limiting reactant

According to the balanced equation, 2 moles of calcium react with 1 mole of oxygen gas.

- From 0.154 mol of calcium, the required moles of \(\text{O}_2\) are:

\[
\text{Required moles of O}_2 = \frac{0.154}{2} = 0.077 \, \text{mol}
\]

Since there are 0.128 mol of \(\text{O}_2\) available, calcium is the limiting reactant.

### Step 3: Calculate the mass of calcium oxide produced

Using the moles of the limiting reactant (calcium), we find the moles of \(\text{CaO}\):

\[
\text{Moles of CaO} = 0.154 \, \text{mol}
\]

**Molar mass of calcium oxide (\(\text{CaO}\))**: \(40.08 + 16.00 = 56.08\) g/mol

\[
\text{Mass of CaO} = 0.154 \, \text{mol} \times 56.08 \, \text{g/mol} \approx 8.63 \, \text{g}
\]

### Final Answer

The mass of calcium oxide that can be prepared is approximately **8.63 g**.

Would you like further details or have any questions?

Here are some related questions you might find helpful:

1. How do you identify the limiting reactant in a chemical reaction?
2. How is the molar mass of a compound calculated?
3. Why is it important to balance a chemical equation before solving stoichiometry problems?
4. What is the significance of significant figures in scientific calculations?
5. How do you determine the theoretical yield of a chemical reaction?

**Tip:** Always ensure that the chemical equation is balanced before performing stoichiometric calculations to obtain accurate results.

Calculate the mass of calcium oxide that can be prepared from 6.17 g of Ca and 4.11 g of O2.

Learn how to calculate the mass of calcium oxide produced from a given mass of calcium and oxygen using stoichiometry, molar mass, and the limiting reactant concept. A step-by-step solution for high school students (Grades 10-12).

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