Math Problem Statement
Determine the theoretical yield (maximum amount of product that can be formed) in grams when 0.486 grams of magnesium are reacted with excess pure oxygen. Hint: Use the balanced equation provided in the experiment.
Solution
To determine the theoretical yield, we'll use the reaction between magnesium (Mg) and oxygen (O₂) to form magnesium oxide (MgO). The balanced chemical equation is:
Step 1: Calculate the moles of magnesium.
The molar mass of magnesium (Mg) is 24.305 g/mol. We can calculate the moles of magnesium used:
Step 2: Use the stoichiometry of the reaction.
From the balanced equation, we know that 2 moles of magnesium react with 1 mole of oxygen to produce 2 moles of magnesium oxide. Therefore, the number of moles of magnesium oxide produced is equal to the number of moles of magnesium reacted:
Step 3: Calculate the mass of magnesium oxide (MgO).
The molar mass of magnesium oxide (MgO) is:
Now, we calculate the mass of MgO produced:
Theoretical Yield:
The theoretical yield of magnesium oxide is 0.806 grams.
Would you like more details or have any questions?
Here are 5 related questions to deepen your understanding:
- What is the limiting reactant in a chemical reaction, and how does it affect the theoretical yield?
- How would you determine the actual yield from an experiment?
- Why is it important to have a balanced chemical equation when calculating theoretical yield?
- How would the theoretical yield change if 1.0 grams of magnesium were used instead of 0.486 grams?
- What are some factors that can cause the actual yield to be lower than the theoretical yield?
Tip: Theoretical yield assumes perfect conditions. Always compare it with actual yield to calculate percent yield!
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Math Problem Analysis
Mathematical Concepts
Stoichiometry
Mole Concept
Chemical Reactions
Formulas
Moles of Mg = Mass of Mg / Molar mass of Mg
Moles of MgO = Moles of Mg (from balanced equation)
Mass of MgO = Moles of MgO * Molar mass of MgO
Theorems
Law of Conservation of Mass
Suitable Grade Level
High School Chemistry (Grades 9-12)
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