A chemist determined by measurements that 0.015 moles of calcium participated in a chemical reaction. Calculate the mass of calcium that participated in the chemical reaction.
Round your answer to 2 significant digits.

To calculate the mass of calcium (Ca) that participated in the chemical reaction, we can use the formula:

\[
\text{Mass} = \text{moles} \times \text{molar mass}
\]

Given:
- Moles of calcium = 0.015 moles
- Molar mass of calcium (Ca) = 40.08 g/mol

Now, let's calculate the mass:

\[
\text{Mass} = 0.015 \, \text{moles} \times 40.08 \, \text{g/mol}
\]

\[
\text{Mass} = 0.6012 \, \text{g}
\]

Rounding the answer to 2 significant digits:

\[
\text{Mass} = 0.60 \, \text{g}
\]

Thus, the mass of calcium that participated in the chemical reaction is **0.60 g**.

Would you like further details or have any questions?

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Here are 5 related questions for further practice:

1. How many moles of calcium are present in 2 grams of calcium?
2. If 0.020 moles of calcium participated, what would be the mass?
3. What is the mass of 1 mole of calcium?
4. How do you calculate the number of moles from a given mass?
5. Why is molar mass important in stoichiometry?

**Tip:** Always ensure that the number of significant digits in your final answer reflects the precision of the values given in the question.

A chemist determined by measurements that 0.015 moles of calcium participated in a chemical reaction. Calculate the mass of calcium that participated in the chemical reaction. Round your answer to 2 significant digits.

Learn how to calculate the mass of calcium that participated in a chemical reaction from 0.015 moles using the formula 'Mass = moles × molar mass'. This problem demonstrates stoichiometric concepts and the use of significant figures, suitable for Grades 9-12.

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