Math Problem Statement

((17100 * .85 * 1) * (.237-0) / 2.1315) * (.237-0) / (.237-0) + (.643 * .3249* ((2.1315 * (.237-0)) ^ .5)))

Solution

Let's break down the expression step by step.

Given the equation:

((17100×0.85×1)×(0.2370)/2.1315)×(0.2370)/(0.2370)+(0.643×0.3249×((2.1315×(0.2370))0.5))((17100 \times 0.85 \times 1) \times (0.237 - 0) / 2.1315) \times (0.237 - 0) / (0.237 - 0) + (0.643 \times 0.3249 \times ((2.1315 \times (0.237 - 0))^{0.5}))

Step 1: Simplify individual components

  • 17100×0.85=1453517100 \times 0.85 = 14535
  • 0.2370=0.2370.237 - 0 = 0.237

So, the expression becomes:

((14535×0.237/2.1315)×0.237/0.237)+(0.643×0.3249×((2.1315×0.237)0.5))\left( (14535 \times 0.237 / 2.1315) \times 0.237 / 0.237 \right) + \left( 0.643 \times 0.3249 \times \left( (2.1315 \times 0.237)^{0.5} \right) \right)

Step 2: Further simplifications

  • 14535×0.237=3440.29514535 \times 0.237 = 3440.295
  • 3440.295/2.13151611.753440.295 / 2.1315 \approx 1611.75

Now, the expression becomes:

(1611.75×0.237/0.237)+(0.643×0.3249×((2.1315×0.237)0.5))(1611.75 \times 0.237 / 0.237) + \left( 0.643 \times 0.3249 \times \left( (2.1315 \times 0.237)^{0.5} \right) \right)

Since 0.237/0.237=10.237 / 0.237 = 1, we simplify this part to:

1611.75+(0.643×0.3249×((2.1315×0.237)0.5))1611.75 + \left( 0.643 \times 0.3249 \times \left( (2.1315 \times 0.237)^{0.5} \right) \right)

Step 3: Evaluate the second part

First, calculate 2.1315×0.237=0.50592.1315 \times 0.237 = 0.5059.

Now, we need to calculate the square root of 0.50590.5059:

0.50590.7113\sqrt{0.5059} \approx 0.7113

Now, multiply:

0.643×0.3249=0.20970.643 \times 0.3249 = 0.2097

So, the second part becomes:

0.2097×0.71130.14960.2097 \times 0.7113 \approx 0.1496

Step 4: Final simplification

Now, add the two parts:

1611.75+0.1496=1611.89961611.75 + 0.1496 = 1611.8996

Final Result:

1611.8996\boxed{1611.8996}

Let me know if you'd like further details or have any questions!

Related Questions:

  1. How does the order of operations affect this type of calculation?
  2. What is the significance of the square root in this context?
  3. Can we use a calculator to simplify this further?
  4. What would happen if we changed the values in the equation?
  5. How do rounding errors affect the final result in real-world scenarios?

Tip: Always ensure to break down complex expressions into smaller parts and simplify each one before combining them for better accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Arithmetic Operations
Square Roots
Order of Operations

Formulas

Order of Operations
Square Root Function

Theorems

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Suitable Grade Level

Grades 9-11