Math Problem Statement

((14600 * .85 * 1 ) * (.207-0) / 2.1315 ) * (.207-0) / (.207-0) + (.643 * .3249* ((2.1315 * ( .207-0 )) ^ .5)))

Solution

Let's break down the expression step by step for clarity and then evaluate it.

The given expression is:

((14600×0.85×1)×0.20702.1315)×0.20700.2070+(0.643×0.3249×(2.1315×(0.2070))0.5)\left( \left( 14600 \times 0.85 \times 1 \right) \times \frac{0.207 - 0}{2.1315} \right) \times \frac{0.207 - 0}{0.207 - 0} + \left( 0.643 \times 0.3249 \times \left( 2.1315 \times (0.207 - 0) \right)^{0.5} \right)

Step 1: Simplify the components

  1. 14600×0.85×1=1241014600 \times 0.85 \times 1 = 12410
  2. 0.2070=0.2070.207 - 0 = 0.207, so we have:
    • The first term becomes:
      12410×0.2072.131512410 \times \frac{0.207}{2.1315}
    • The second term becomes: 0.207/0.207=10.207 / 0.207 = 1

So, the first part of the equation simplifies to: 12410×0.2072.1315×112410 \times \frac{0.207}{2.1315} \times 1

  1. For the second term:
    • First, calculate: 2.1315×0.207=0.44146052.1315 \times 0.207 = 0.4414605
    • Then raise this to the power of 0.50.5: 0.44146050.5=0.66410.4414605^{0.5} = 0.6641
    • Now multiply by 0.6430.643 and 0.32490.3249: 0.643×0.3249×0.6641=0.14170.643 \times 0.3249 \times 0.6641 = 0.1417

Step 2: Combine both parts

Now, we compute each part:

  1. First term: 12410×0.2072.1315=12410×0.09711204.112410 \times \frac{0.207}{2.1315} = 12410 \times 0.0971 \approx 1204.1

  2. Add the second term: 1204.1+0.1417=1204.24171204.1 + 0.1417 = 1204.2417

Final Answer:

1204.24171204.2417

Would you like more details on any of these steps? Feel free to ask if anything is unclear!

Related Questions:

  1. How would the result change if 0.2070.207 was replaced with a higher value, say 0.30.3?
  2. How do the square root and exponentiation steps influence the outcome of such expressions?
  3. How can we apply similar formulas in real-life scenarios, such as in economics or engineering?
  4. What happens if we reduce 2.13152.1315 in the denominator?
  5. How would the result change if the multiplication factor (e.g., 0.85) was adjusted?

Tip: When dealing with complex formulas, break them into smaller parts and simplify each step before combining them to avoid calculation mistakes!

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Math Problem Analysis

Mathematical Concepts

Algebra
Arithmetic Operations
Exponents and Square Roots

Formulas

Basic arithmetic operations
Exponentiation formula
Square root formula

Theorems

Order of Operations (PEMDAS)

Suitable Grade Level

Grades 10-12