Math Problem Statement

solve by steepest descent method

solve by steepest descent method

Solution

To solve this optimization problem using the steepest descent method, we'll follow a systematic approach. Here's the given function and the starting point:

Given:

f(x1,x2)=x1x2+2x12+2x1x2+x22f(x_1, x_2) = x_1 - x_2 + 2x_1^2 + 2x_1x_2 + x_2^2

  • Starting point: (x1,x2)=(0,0)(x_1, x_2) = (0, 0)

Steps for the Steepest Descent Method:

  1. Compute the gradient of the function f(x1,x2)f(x_1, x_2).
  2. Evaluate the gradient at the starting point.
  3. Determine the search direction as the negative gradient.
  4. Perform a line search to find the optimal step size along the search direction.
  5. Update the point and repeat the process until convergence.

Let's go through these steps.

Step 1: Compute the Gradient

The gradient f(x1,x2)\nabla f(x_1, x_2) consists of the partial derivatives with respect to x1x_1 and x2x_2:

fx1=1+4x1+2x2\frac{\partial f}{\partial x_1} = 1 + 4x_1 + 2x_2 fx2=1+2x1+2x2\frac{\partial f}{\partial x_2} = -1 + 2x_1 + 2x_2

Thus, the gradient is: f(x1,x2)=(1+4x1+2x2,1+2x1+2x2)\nabla f(x_1, x_2) = \left( 1 + 4x_1 + 2x_2, -1 + 2x_1 + 2x_2 \right)

Step 2: Evaluate the Gradient at the Starting Point (0,0)(0, 0)

At the point (x1,x2)=(0,0)(x_1, x_2) = (0, 0): f(0,0)=(1+4(0)+2(0),1+2(0)+2(0))=(1,1)\nabla f(0, 0) = \left( 1 + 4(0) + 2(0), -1 + 2(0) + 2(0) \right) = (1, -1)

Step 3: Determine the Search Direction

The search direction pp is the negative of the gradient: p=f(0,0)=(1,1)p = -\nabla f(0, 0) = (-1, 1)

Step 4: Perform a Line Search

We need to find the optimal step size α\alpha that minimizes f(x1,x2)f(x_1, x_2) along the direction p=(1,1)p = (-1, 1).

Let the new point be: (x1,x2)=(0,0)+α(1,1)=(α,α)(x_1, x_2) = (0, 0) + \alpha(-1, 1) = (-\alpha, \alpha) Substituting into the function f(x1,x2)f(x_1, x_2): f(α,α)=αα+2(α)2+2(α)(α)+α2f(-\alpha, \alpha) = -\alpha - \alpha + 2(-\alpha)^2 + 2(-\alpha)(\alpha) + \alpha^2 Simplifying: f(α,α)=2α+2α22α2+α2=2α+α2f(-\alpha, \alpha) = -2\alpha + 2\alpha^2 - 2\alpha^2 + \alpha^2 = -2\alpha + \alpha^2 To minimize this with respect to α\alpha, we take the derivative: ddα(2α+α2)=2+2α\frac{d}{d\alpha}(-2\alpha + \alpha^2) = -2 + 2\alpha Setting this equal to 0: 2+2α=0α=1-2 + 2\alpha = 0 \quad \Rightarrow \quad \alpha = 1

Step 5: Update the Point

Using α=1\alpha = 1, the new point is: (x1,x2)=(0,0)+1(1,1)=(1,1)(x_1, x_2) = (0, 0) + 1(-1, 1) = (-1, 1)

Now, we can repeat the process starting from the new point (1,1)(-1, 1). The iterations continue until the gradient is close to zero or the change in the function value is sufficiently small.

Do you want to continue with additional iterations, or do you have any questions?

Here are 5 relative questions:

  1. How does the steepest descent method compare with Newton's method in terms of convergence speed?
  2. What are the potential issues with using a fixed step size in the steepest descent method?
  3. How can we modify the steepest descent method to improve convergence?
  4. What role does the gradient play in optimization problems?
  5. How can you determine when to stop the iteration process in steepest descent?

Tip: In optimization, choosing the correct step size is crucial; adaptive methods like line search can improve convergence.

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Math Problem Analysis

Mathematical Concepts

Optimization
Calculus
Gradient Descent

Formulas

f(x1, x2) = x1 - x2 + 2x1^2 + 2x1x2 + x2^2
∇f(x1, x2) = (1 + 4x1 + 2x2, -1 + 2x1 + 2x2)

Theorems

Steepest Descent Method

Suitable Grade Level

College Level