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The given function is \( f(x) = \sqrt{x - 2} \).

### To find the domain of the function:

1. For a square root function, the expression under the square root must be non-negative, since the square root of a negative number is not defined in the set of real numbers.
   
2. So, we need:
   \[
   x - 2 \geq 0
   \]

3. Solving for \( x \):
   \[
   x \geq 2
   \]

### Therefore, the domain of the function \( f(x) = \sqrt{x - 2} \) is \( x \geq 2 \).

This corresponds to the answer choice that indicates \( x \geq 2 \).

Would you like more details on how I derived this? Here are five related questions for practice:

1. What is the domain of the function \( g(x) = \sqrt{3x - 6} \)?
2. How do you determine the domain of a square root function in general?
3. What is the domain of \( h(x) = \sqrt{-x + 5} \)?
4. If the function is \( f(x) = \sqrt{x^2 - 4x + 3} \), how do you find its domain?
5. What is the range of \( f(x) = \sqrt{x - 2} \)?

**Tip**: Always remember, for square root functions, the expression inside the root must be non-negative to ensure real number results!

What is the domain of the function f(x) = √(x - 2)?

Understand how to find the domain of the square root function f(x) = √(x - 2) by solving the inequality x - 2 >= 0. This problem covers algebraic concepts of inequalities and square roots, suitable for students in Grades 8-10.

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