Math Problem Statement

Consider a triangle ABC where b = 46, a = 60, and B = 112°. Solve the triangle to find angles A, C, and side c using the Law of Sines.

Solution

To solve the triangle ABC\triangle ABC using the Law of Sines, follow these steps:

Given:

  • b=46b = 46
  • a=60a = 60
  • B=112B = 112^\circ

We need to find:

  1. CC (angle)
  2. cc (side)
  3. AA (angle)

Step 1: Find angle AA

Using the angle sum property of a triangle: A+B+C=180A + B + C = 180^\circ A=180BC=180112CA = 180^\circ - B - C = 180^\circ - 112^\circ - C We will calculate AA after finding CC.

Step 2: Use the Law of Sines to find CC

The Law of Sines states: asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} Using bsinB=csinC\frac{b}{\sin B} = \frac{c}{\sin C}: c=bsinCsinBc = b \cdot \frac{\sin C}{\sin B} We’ll calculate sinB\sin B and other values once we know CC.


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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Angle Sum Property of a Triangle

Formulas

Angle sum property: A + B + C = 180°
Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)

Theorems

Law of Sines
Triangle Angle Sum Theorem

Suitable Grade Level

Grades 10-12