Math Problem Statement

Solve the following system by the method of reduction: 3x - 6z = 18 x - 3y - 3z = 29 x + y - 3z = 1 4x + y + z = -1 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.

Solution

Let's solve the system of equations by the method of elimination (or reduction) to find the values of xx, yy, and zz.

Given system:

  1. 3x6z=183x - 6z = 18
  2. x3y3z=29x - 3y - 3z = 29
  3. x+y3z=1x + y - 3z = 1
  4. 4x+y+z=14x + y + z = -1

Step 1: Simplify Equations if Possible

From equation (1): 3x6z=183x - 6z = 18 Divide by 3: x2z=6(Equation A)x - 2z = 6 \quad \text{(Equation A)}

Step 2: Use Equation A to Substitute and Eliminate Variables

Using x=6+2zx = 6 + 2z from Equation A, substitute xx in the remaining equations (2), (3), and (4) to eliminate xx.

Substitute into Equation (2):

(6+2z)3y3z=29(6 + 2z) - 3y - 3z = 29 Simplify: 63yz=296 - 3y - z = 29 3yz=23(Equation B)-3y - z = 23 \quad \text{(Equation B)}

Substitute into Equation (3):

(6+2z)+y3z=1(6 + 2z) + y - 3z = 1 Simplify: 6+yz=16 + y - z = 1 yz=5(Equation C)y - z = -5 \quad \text{(Equation C)}

Substitute into Equation (4):

4(6+2z)+y+z=14(6 + 2z) + y + z = -1 24+8z+y+z=124 + 8z + y + z = -1 Combine terms: y+9z=25(Equation D)y + 9z = -25 \quad \text{(Equation D)}

Step 3: Solve Equations B, C, and D

Now we have three equations in terms of yy and zz:

  1. 3yz=23-3y - z = 23 (Equation B)
  2. yz=5y - z = -5 (Equation C)
  3. y+9z=25y + 9z = -25 (Equation D)

Solve Equation B and C

From Equation C: y=5+zy = -5 + z Substitute y=5+zy = -5 + z into Equation B: 3(5+z)z=23-3(-5 + z) - z = 23 153zz=2315 - 3z - z = 23 154z=2315 - 4z = 23 4z=8-4z = 8 z=2z = -2

Substitute z=2z = -2 into Equation C to Find yy

y=5+(2)y = -5 + (-2) y=7y = -7

Substitute y=7y = -7 and z=2z = -2 into Equation A to Find xx

x2(2)=6x - 2(-2) = 6 x+4=6x + 4 = 6 x=2x = 2

Solution

The solution to the system is: x=2,y=7,z=2x = 2, \quad y = -7, \quad z = -2

Would you like further details or have any questions?


Related Questions

  1. What is the elimination (reduction) method in solving systems of equations?
  2. How do substitution and elimination methods compare in solving systems?
  3. Can all systems of equations be solved by elimination? Why or why not?
  4. What does it mean if a system of equations has no solution?
  5. How would the solution change if one of the constants in the system was altered?

Tip

Always check your solution by substituting back into the original equations to ensure accuracy.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Equations
Elimination Method

Formulas

Substitution and elimination for systems of equations

Theorems

Elimination method for solving linear systems

Suitable Grade Level

Grades 9-12