Math Problem Statement

A florist bought daffodils, hyacinths, and tulips which totaled 1,025 flowers altogether. The number of tulips he purchased was 85 flowers more than the number of hyacinths. The number of daffodils was 100 flowers less than double the number of hyacinths. How many of each flower did the florist buy?

Solution

Let's solve the problem step by step based on the given information:

  1. The florist bought daffodils, hyacinths, and tulips totaling 1,025 flowers altogether.
  2. The number of tulips was 85 flowers more than the number of hyacinths.
  3. The number of daffodils was 100 flowers less than double the number of hyacinths.

Let's denote:

  • hh as the number of hyacinths
  • tt as the number of tulips
  • dd as the number of daffodils

The equations based on the information are: t=h+85t = h + 85 d=2h100d = 2h - 100 h+t+d=1025h + t + d = 1025

Now substitute the expressions for tt and dd into the total flowers equation: h+(h+85)+(2h100)=1025h + (h + 85) + (2h - 100) = 1025 4h15=10254h - 15 = 1025 4h=10404h = 1040 h=260h = 260

Now, calculate tt and dd: t=h+85=260+85=345t = h + 85 = 260 + 85 = 345 d=2h100=2×260100=420d = 2h - 100 = 2 \times 260 - 100 = 420

Therefore, the florist bought:

  • 260 hyacinths
  • 345 tulips
  • 420 daffodils

If you have any questions or need further details, feel free to ask! Here are five related questions you might consider:

  1. What if the total number of flowers were different? How would that affect the solution?
  2. What happens if the number of tulips is less than the number of hyacinths? How would the equations change?
  3. Can you solve the problem if the relation between daffodils and hyacinths was given as a ratio instead of a difference?
  4. What kind of problems can be solved using systems of linear equations like this one?
  5. How does changing the number of one type of flower affect the numbers of the others?

Tip: When dealing with word problems, it's helpful to assign variables to unknown quantities and carefully translate the words into algebraic equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations

Formulas

t = h + 85
d = 2h - 100
h + t + d = 1025

Theorems

Substitution method

Suitable Grade Level

Grades 8-10