Math Problem Statement

Billy's restaurant ordered 200 flowers for Mother's Day. They ordered carnations at $1.50 each, roses at $5.75 each, and daisies at $2.60 each. they ordered mostly carnations, and 20 fewer roses than daisies. the total order came to $589.50. How do i find out how many of each type of flower was ordered?

Solution

To find out how many carnations, roses, and daisies were ordered, let's define some variables and set up a system of equations:

Step 1: Define the variables

Let:

  • cc be the number of carnations ordered.
  • rr be the number of roses ordered.
  • dd be the number of daisies ordered.

Step 2: Write equations based on the problem

  1. Total number of flowers:
    Billy's restaurant ordered 200 flowers, so: c+r+d=200c + r + d = 200

  2. Price equation:
    The total cost of the flowers is $589.50. The carnations cost $1.50 each, roses cost $5.75 each, and daisies cost $2.60 each. Therefore, we can write the total price equation as: 1.50c+5.75r+2.60d=589.501.50c + 5.75r + 2.60d = 589.50

  3. Relationship between roses and daisies:
    The problem says they ordered 20 fewer roses than daisies, so: r=d20r = d - 20

Step 3: Substitute and solve the system of equations

We now have three equations:

  1. c+r+d=200c + r + d = 200
  2. 1.50c+5.75r+2.60d=589.501.50c + 5.75r + 2.60d = 589.50
  3. r=d20r = d - 20

Start by substituting r=d20r = d - 20 into the first two equations.

Equation 1:

c+(d20)+d=200c + (d - 20) + d = 200 Simplifying: c+2d20=200orc+2d=220c + 2d - 20 = 200 \quad \text{or} \quad c + 2d = 220 So we get: c=2202d(Equation 4)c = 220 - 2d \quad \text{(Equation 4)}

Equation 2:

Substitute r=d20r = d - 20 into the price equation: 1.50c+5.75(d20)+2.60d=589.501.50c + 5.75(d - 20) + 2.60d = 589.50 Simplify this: 1.50c+5.75d115+2.60d=589.501.50c + 5.75d - 115 + 2.60d = 589.50 1.50c+8.35d=704.50(Equation 5)1.50c + 8.35d = 704.50 \quad \text{(Equation 5)}

Step 4: Substitute c=2202dc = 220 - 2d into Equation 5

Substitute Equation 4 into Equation 5: 1.50(2202d)+8.35d=704.501.50(220 - 2d) + 8.35d = 704.50 Simplifying: 3303d+8.35d=704.50330 - 3d + 8.35d = 704.50 330+5.35d=704.50330 + 5.35d = 704.50 5.35d=374.505.35d = 374.50 d=374.505.3570d = \frac{374.50}{5.35} \approx 70

Step 5: Find rr and cc

Now that we know d70d \approx 70, we can find rr and cc:

  • r=d20=7020=50r = d - 20 = 70 - 20 = 50
  • c=2202d=2202(70)=80c = 220 - 2d = 220 - 2(70) = 80

Final Answer:

  • Carnations: 8080
  • Roses: 5050
  • Daisies: 7070

These are the number of each type of flower ordered.

Would you like a breakdown of any specific step?

Here are 5 related questions for practice:

  1. What would be the total cost if the price of daisies increased by $1 each?
  2. If the total number of flowers ordered was 250, how would the solution change?
  3. What if the restaurant ordered 10 more roses than daisies instead of 20 fewer?
  4. How would the system change if the cost of carnations was $2 each?
  5. What if the total cost of the flowers was $700 instead of $589.50?

Tip: Solving systems of equations step-by-step, especially with substitution, helps to avoid mistakes in calculations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Equations
Substitution Method

Formulas

Total number of flowers: c + r + d = 200
Price equation: 1.50c + 5.75r + 2.60d = 589.50
Relationship between roses and daisies: r = d - 20

Theorems

Substitution Method for Solving Systems of Equations

Suitable Grade Level

Grades 9-11