Math Problem Statement

Solve the system of linear equations using the elimination method.

xx

plus+

yy

plus+

zz

equals=

66

2 x2x

minus−

yy

minus−

6 z6z

equals=

negative 34−34

negative x−x

minus−

yy

plus+

8 z8z

equals=

3939

Question content area bottom

Part 1

The unique solution to the system is

Solution

To solve this system of linear equations using the elimination method, let's start by defining the system clearly and then apply elimination steps:

Given equations:

x+y+z=66x + y + z = 66 2xy6z=342x - y - 6z = -34 xy+8z=39-x - y + 8z = 39

Step 1: Eliminate yy by combining equations

  1. Add the first and second equations to eliminate yy: (x+y+z)+(2xy6z)=66+(34)(x + y + z) + (2x - y - 6z) = 66 + (-34) Simplifying this: 3x5z=323x - 5z = 32

  2. Add the first and third equations to eliminate yy as well: (x+y+z)+(xy+8z)=66+39(x + y + z) + (-x - y + 8z) = 66 + 39 Simplifying this: 9z=1059z = 105 Solving for zz: z=1059=11.67z = \frac{105}{9} = 11.67

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Math Problem Analysis

Mathematical Concepts

Algebra
System of Linear Equations
Elimination Method

Formulas

Linear equation form: ax + by + cz = d
Elimination steps to isolate variables

Theorems

Properties of Equality
Linear Combination in Systems of Equations

Suitable Grade Level

Grades 10-12