Math Problem Statement
Solve the system of equations below: 3x - 6y = 24 and 4x + 5y = -7.
Solution
The system of equations given in the image is:
1) & \quad 3x - 6y = 24 \\ 2) & \quad 4x + 5y = -7 \end{aligned}$$ To solve this system, we'll use either the substitution method or the elimination method. I'll use the elimination method here. ### Step 1: Multiply the equations to align coefficients for elimination To eliminate $$x$$, we can multiply the first equation by 4 and the second equation by 3: $$\begin{aligned} (1) \times 4 & : \quad 12x - 24y = 96 \\ (2) \times 3 & : \quad 12x + 15y = -21 \end{aligned}$$ ### Step 2: Subtract the equations Now, subtract the second equation from the first to eliminate $$x$$: $$(12x - 24y) - (12x + 15y) = 96 - (-21)$$ Simplifying, we get: $$-39y = 117$$ ### Step 3: Solve for $$y$$ Divide both sides by -39: $$y = \frac{117}{-39} = -3$$ ### Step 4: Substitute $$y = -3$$ back into one of the original equations Substitute $$y = -3$$ into the first equation $$3x - 6y = 24$$: $$3x - 6(-3) = 24$$ Simplifying: $$3x + 18 = 24$$ Subtract 18 from both sides: $$3x = 6$$ Divide by 3: $$x = 2$$ ### Solution The solution to the system of equations is: $$x = 2, \quad y = -3$$ Would you like more details or have any questions? Here are 5 related questions you might find interesting: 1. How can we verify the solution to a system of linear equations? 2. What is the difference between the substitution method and the elimination method? 3. How can graphing be used to solve a system of equations? 4. How do you solve a system of equations that has no solution or infinite solutions? 5. How can systems of equations be applied to real-world problems? **Tip:** Always double-check your solution by substituting the values of $$x$$ and $$y$$ back into the original equations. This ensures that the solution satisfies both equations.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Algebra
System of Linear Equations
Elimination Method
Formulas
Elimination method for solving systems of equations
Theorems
None specific; standard algebraic principles are applied.
Suitable Grade Level
Grades 9-12
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