You provided two linear equations:

1. $3x + 5y - 1 = 0$
2. $2x + 3y + 5 = 0$

It seems like you're asking for the solution to this system of equations. Let's solve it using either substitution or elimination. I will use the elimination method.

Step 1: Align the system of equations

We have: 3x + 5y = 1 \tag{1} 2x + 3y = -5 \tag{2}

Step 2: Eliminate one variable (let's eliminate $x$)

To eliminate $x$, multiply the first equation by 2 and the second equation by 3 to align the coefficients of $x$: 6x + 10y = 2 \tag{3} 6x + 9y = -15 \tag{4}

Step 3: Subtract Equation (4) from Equation (3)

$(6x + 10y) - (6x + 9y) = 2 - (-15)$ $6x + 10y - 6x - 9y = 2 + 15$ $y = 17$

Step 4: Substitute $y = 17$ into one of the original equations

Substitute $y = 17$ into Equation (1): $3x + 5(17) = 1$ $3x + 85 = 1$ $3x = 1 - 85$ $3x = -84$ $x = -28$

Solution:

The solution to the system is: $x = -28, \quad y = 17$

Would you like more details on any part of the process or have any questions?

Related Questions:

1. How do you solve a system of equations using the substitution method?
2. What is the graphical interpretation of solving a system of linear equations?
3. How do you verify the solution of a system of equations?
4. Can systems of linear equations have no solutions or infinitely many solutions?
5. What are some applications of systems of equations in real-world problems?

Tip: Always double-check your solutions by plugging the values of $x$ and $y$ back into the original equations to ensure correctness.