Math Problem Statement

if a+b +c =24 ab/2=24 find a,b,c

Solution

We are given the following system of equations:

  1. a+b+c=24a + b + c = 24
  2. ab2=24\frac{ab}{2} = 24, which simplifies to ab=48ab = 48.

To solve for aa, bb, and cc, let's proceed step by step.

Step 1: Express abab in terms of a single variable

From the second equation: ab=48.ab = 48. This means aa and bb are factors of 48. Possible pairs (a,b)(a, b) can be:

  • (1,48)(1, 48)
  • (2,24)(2, 24)
  • (3,16)(3, 16)
  • (4,12)(4, 12)
  • (6,8)(6, 8)
  • (8,6)(8, 6)
  • (12,4)(12, 4)
  • (16,3)(16, 3)
  • (24,2)(24, 2)
  • (48,1)(48, 1)

Step 2: Use the sum equation

From the first equation: a+b+c=24,a + b + c = 24, we can solve for cc: c=24(a+b).c = 24 - (a + b). Now, we substitute the values of aa and bb from the factor pairs into this equation to find cc.

Step 3: Check for valid solutions

Let's check each pair:

  1. For a=1a = 1, b=48b = 48, we get: c=24(1+48)=2449=25.c = 24 - (1 + 48) = 24 - 49 = -25. This gives a negative value for cc, which may not be valid in this context.

  2. For a=2a = 2, b=24b = 24, we get: c=24(2+24)=2426=2.c = 24 - (2 + 24) = 24 - 26 = -2. Again, cc is negative.

  3. For a=3a = 3, b=16b = 16, we get: c=24(3+16)=2419=5.c = 24 - (3 + 16) = 24 - 19 = 5. This gives a positive value for cc, and is a valid solution.

  4. For a=4a = 4, b=12b = 12, we get: c=24(4+12)=2416=8.c = 24 - (4 + 12) = 24 - 16 = 8. This is also a valid solution.

  5. For a=6a = 6, b=8b = 8, we get: c=24(6+8)=2414=10.c = 24 - (6 + 8) = 24 - 14 = 10. This is another valid solution.

Thus, we have three valid solutions:

  • a=3a = 3, b=16b = 16, c=5c = 5,
  • a=4a = 4, b=12b = 12, c=8c = 8,
  • a=6a = 6, b=8b = 8, c=10c = 10.

Step 4: Final solutions

The possible sets of values for aa, bb, and cc are:

  1. a=3a = 3, b=16b = 16, c=5c = 5,
  2. a=4a = 4, b=12b = 12, c=8c = 8,
  3. a=6a = 6, b=8b = 8, c=10c = 10.

Would you like more details or further clarification on any of these steps? Here are a few follow-up questions to help:

  1. How do you check the consistency of multiple solutions in systems of equations?
  2. What are some real-life applications of solving systems like these?
  3. How can you extend this type of problem to include more variables?
  4. What would happen if one of the numbers were constrained to be negative?
  5. How do you recognize when a system has multiple valid solutions?

Tip: When dealing with factorizations like ab=48ab = 48, listing the possible factor pairs is an efficient way to find potential solutions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Equations
Factorization

Formulas

a + b + c = 24
ab = 48 (from ab/2 = 24)

Theorems

Factor Pairs
Solving Systems of Equations

Suitable Grade Level

Grades 8-10