Math Problem Statement

if i have 30 pears, i eat five, then five more, then buy five more, then eat five more, then eat five more, then buy five more, then eat five more, then eat five more, then buy five more, then buy five more, then eat five more, the eat 10, then eat 2, then eat 3, then buy 5, then eat five, how many would i have

Solution

Let's break down the sequence of events step by step:

  1. Starting pears: 30
  2. Eat 5: 305=2530 - 5 = 25
  3. Eat 5 more: 255=2025 - 5 = 20
  4. Buy 5: 20+5=2520 + 5 = 25
  5. Eat 5 more: 255=2025 - 5 = 20
  6. Eat 5 more: 205=1520 - 5 = 15
  7. Buy 5: 15+5=2015 + 5 = 20
  8. Eat 5 more: 205=1520 - 5 = 15
  9. Eat 5 more: 155=1015 - 5 = 10
  10. Buy 5: 10+5=1510 + 5 = 15
  11. Buy 5 more: 15+5=2015 + 5 = 20
  12. Eat 5 more: 205=1520 - 5 = 15
  13. Eat 10: 1510=515 - 10 = 5
  14. Eat 2: 52=35 - 2 = 3
  15. Eat 3: 33=03 - 3 = 0
  16. Buy 5: 0+5=50 + 5 = 5
  17. Eat 5: 55=05 - 5 = 0

After following all these steps, you would have 0 pears left.

Would you like further details or have any questions?


Here are 5 related questions to consider:

  1. What would happen if you started with more pears?
  2. How many pears do you buy in total?
  3. How many pears do you eat in total?
  4. What if you added or subtracted more steps?
  5. What would be the outcome if you ate fewer pears each time?

Tip: When solving problems with a sequence of operations, writing each step out clearly helps in keeping track of the changes.

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Operations with integers

Formulas

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Theorems

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Suitable Grade Level

Grades 4-6