Apples cost $0.60 each and pears cost $0.80 each. If a total of 130 apples and pears cost $88, how many pears were there? don't use algebra

To solve this problem without using algebra, we can use a logical approach by trial and error. Let's break it down step by step:

1. **Assume all 130 fruits were apples:**  
   - The cost would be $130 \times 0.60 = 78$ dollars.  
   - But the total cost is $88, so the difference is $88 - 78 = 10$ dollars.

2. **Now, replace some apples with pears:**  
   - Each pear costs $0.20 more than an apple.  
   - To make up the $10 difference, divide the difference by $0.20:
     \[
     \frac{10}{0.20} = 50
     \]
   - So, you would need to replace 50 apples with 50 pears.

3. **Conclusion:**  
   - There were 50 pears and $130 - 50 = 80$ apples.

So, there were **50 pears**.

Would you like more details on this or have any questions? Here are 5 related questions you might find interesting:

1. What if the cost per apple was $0.50 and per pear was $1.00?
2. How would the solution change if the total number of fruits was 150 instead of 130?
3. What if the total cost was $100 instead of $88?
4. How would you solve it if pears cost $1.20 and apples $0.80?
5. How can we solve similar problems using a table or diagram?

**Tip:** In problems like these, finding the difference in cost per item helps to determine the number of one type that needs to be substituted for another.

Learn how to solve the problem involving the cost of apples and pears. Discover a logical approach to determine the number of pears when given the total number of fruits and their combined cost. Suitable for Grades 5-6.

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