To solve this problem without using algebra, we can use a logical approach by trial and error. Let's break it down step by step:

1. Assume all 130 fruits were apples:

   • The cost would be $130 \times 0.60 = 78$ dollars.
   • But the total cost is $88, so the difference is $88 - 78 = 10$ dollars.

2. Now, replace some apples with pears:

   • Each pear costs $0.20 more than an apple.
   • To make up the $10 difference, divide the difference by $0.20: $\frac{10}{0.20} = 50$
   • So, you would need to replace 50 apples with 50 pears.

3. Conclusion:

   • There were 50 pears and $130 - 50 = 80$ apples.

So, there were 50 pears.

Would you like more details on this or have any questions? Here are 5 related questions you might find interesting:

1. What if the cost per apple was $0.50 and per pear was $1.00?
2. How would the solution change if the total number of fruits was 150 instead of 130?
3. What if the total cost was $100 instead of $88?
4. How would you solve it if pears cost $1.20 and apples $0.80?
5. How can we solve similar problems using a table or diagram?

Tip: In problems like these, finding the difference in cost per item helps to determine the number of one type that needs to be substituted for another.