Math Problem Statement

Solve the differential equation dy/dx = e^(x-y).

Solution

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Let's begin.The image contains a mathematical equation:

dydx=exy\frac{dy}{dx} = e^{x-y}

This is a separable differential equation, which means we can rearrange it to separate variables xx and yy. Here's how to solve it step-by-step:

Step 1: Rewrite the equation to separate variables

We want all the yy-related terms on one side and the xx-related terms on the other side. Start by rewriting the equation:

dydx=exy=exey\frac{dy}{dx} = e^{x-y} = e^x e^{-y}

Now, separate the variables:

eydy=exdxe^y \, dy = e^x \, dx

Step 2: Integrate both sides

Integrate both sides of the equation:

eydy=exdx\int e^y \, dy = \int e^x \, dx

On the left-hand side, the integral of eye^y is eye^y, and on the right-hand side, the integral of exe^x is exe^x:

ey=ex+Ce^y = e^x + C

where CC is the constant of integration.

Step 3: Solve for yy

Now, take the natural logarithm of both sides to solve for yy:

y=ln(ex+C)y = \ln(e^x + C)

Thus, the solution to the differential equation is:

y=ln(ex+C)y = \ln(e^x + C)

This is the general solution to the given differential equation.

Do you need further details or clarification? Here are some additional questions to explore:

  1. What happens to the solution when C=0C = 0?
  2. How can we check the solution by differentiating it?
  3. What is the particular solution if an initial condition is given, such as y(0)=1y(0) = 1?
  4. What would the graph of y=ln(ex+C)y = \ln(e^x + C) look like?
  5. How can we interpret this solution in terms of exponential growth or decay?

Tip: When solving separable differential equations, always make sure to check whether the variables can be separated before starting the integration process.

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Math Problem Analysis

Mathematical Concepts

Calculus
Differential Equations
Separable Equations

Formulas

Separation of variables: e^y dy = e^x dx
Integration: ∫e^y dy = ∫e^x dx

Theorems

Separation of Variables Theorem

Suitable Grade Level

College Level