Math Problem Statement
(c) x(e
ସ௬ − 1) ௗ௬
ௗ௫
- (x
ଶ − 1)e
ଶ௬ = 0, x > 0 solve using separation of variables
Solution
We are given the differential equation:
We will solve this using the method of separation of variables.
Step 1: Rewriting the equation
We start by rewriting the equation:
Now, divide both sides by :
Step 2: Separate the variables
We want to separate the variables and . So, divide both sides by and multiply by :
Step 3: Integrate both sides
Now we can integrate both sides. The left side requires integrating with respect to , and the right side with respect to .
For the left side:
The left-hand side simplifies to:
For the right-hand side, we simplify the integrand:
Now integrate:
Step 4: Combine the results
We now combine both results from the integrals:
Where is the constant of integration. Simplifying, we get:
Step 5: Solve for
Now, solve for by taking the natural logarithm of both sides:
Thus, the solution to the differential equation is:
Summary
Using separation of variables, we have solved the differential equation and obtained the general solution for in terms of .
Would you like more details on any of the steps?
Here are some related questions to deepen your understanding:
- How can separation of variables be applied to other types of differential equations?
- What is the importance of the constant of integration in solving differential equations?
- How do you handle boundary conditions or initial conditions when solving differential equations?
- Why is it necessary to check the domain of the solution after solving?
- Can the method of separation of variables be extended to partial differential equations?
Tip: Always check the consistency of units or dimensions when solving physical problems involving differential equations.
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Math Problem Analysis
Mathematical Concepts
Differential Equations
Separation of Variables
Integration Techniques
Formulas
\frac{dy}{dx} = -(x^2 - 1) e^y / x
\int \frac{dy}{e^y} = \int - \frac{(x^2 - 1)}{x} dx
e^{-y} = \frac{x^2}{2} - \ln |x| - C
Theorems
Separation of Variables Method
Integration by Substitution
Suitable Grade Level
College Level
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