The inequality you provided is:

\[
\frac{-2x + 1}{x - 3} \leq 0
\]

To solve this inequality, let's break it down into a step-by-step process.

### Step 1: Identify the critical points
We need to find the values of \(x\) that make the expression either 0 or undefined:

1. Set the numerator equal to 0:
   \[
   -2x + 1 = 0 \implies x = \frac{1}{2}
   \]
   
2. Set the denominator equal to 0 (where the expression is undefined):
   \[
   x - 3 = 0 \implies x = 3
   \]

So, the critical points are \(x = \frac{1}{2}\) and \(x = 3\).

### Step 2: Analyze the sign of the expression
Now, we need to determine the sign of the expression on the intervals created by these critical points: \( (-\infty, \frac{1}{2}) \), \( (\frac{1}{2}, 3) \), and \( (3, \infty) \).

- For \(x \in (-\infty, \frac{1}{2})\), pick a test point like \(x = 0\):
  \[
  \frac{-2(0) + 1}{0 - 3} = \frac{1}{-3} = -\frac{1}{3}
  \]
  This is negative.

- For \(x \in (\frac{1}{2}, 3)\), pick a test point like \(x = 1\):
  \[
  \frac{-2(1) + 1}{1 - 3} = \frac{-2 + 1}{-2} = \frac{-1}{-2} = \frac{1}{2}
  \]
  This is positive.

- For \(x \in (3, \infty)\), pick a test point like \(x = 4\):
  \[
  \frac{-2(4) + 1}{4 - 3} = \frac{-8 + 1}{1} = -7
  \]
  This is negative.

### Step 3: Check the inequality
We want the expression to be less than or equal to 0, so we are looking for intervals where the expression is negative or zero.

- The expression is **negative** on the intervals \( (-\infty, \frac{1}{2}) \) and \( (3, \infty) \).
- The expression is **zero** at \(x = \frac{1}{2}\).

### Step 4: Conclusion
The solution to the inequality is:
\[
x \in (-\infty, \frac{1}{2}] \cup (3, \infty)
\]

This is the set of values for \(x\) that satisfy the inequality.

Would you like further details or have any questions?

Here are 5 related questions to expand on this:

1. How do you solve rational inequalities involving different expressions?
2. What happens when both the numerator and denominator have higher-degree terms?
3. How do vertical asymptotes affect the solution to inequalities?
4. Can inequalities have multiple valid solution intervals?
5. What are the properties of rational expressions when analyzing their sign?

**Tip:** Always carefully handle points where the expression is undefined, as these create important boundaries in rational inequalities.

Learn how to solve the rational inequality (-2x + 1) / (x - 3) ≤ 0 using critical point analysis and sign testing. This step-by-step solution covers rational inequalities, critical points, and how to determine the sign of the expression. Suitable for Grades 10-12.

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