Math Problem Statement

Refer to the following diagram for the roof of a house. In the figure, x is the length of a rafter measured from the top of a wall to the top of the roof; 𝜃 is the acute angle between a rafter and the horizontal; and h is the vertical distance from the top of the wall to the top of the roof.

Suppose that 𝜃 = 31° and h = 32.5 ft.

(a) Determine x. Round the answer to one decimal place. x =  ft

(b) Find the area of the gable. Round the final answer to one decimal place. [The gable is the triangular region bounded by the rafters and the attic floor.] ft2

Solution

We are given a diagram of the roof of a house with certain known values and need to find:

  • (a) The length of a rafter (x) using the given angle (𝜃) and vertical height (h).
  • (b) The area of the gable, which is the triangular region bounded by the rafters and the attic floor.

(a) Finding x

The triangle formed by the roof rafters is a right triangle, where:

  • x is the hypotenuse (length of the rafter),
  • h is the vertical leg (opposite the angle 𝜃),
  • and the acute angle 𝜃 = 31° is between the rafter and the horizontal.

We can use the sine function because: sin(𝜃)=oppositehypotenuse=hx\sin(𝜃) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{h}{x} Thus: x=hsin(𝜃)x = \frac{h}{\sin(𝜃)} Substitute the known values: x=32.5ftsin(31)x = \frac{32.5 \, \text{ft}}{\sin(31^\circ)}

Let’s calculate x.

(b) Finding the area of the gable

The gable forms a right triangle, and the area of a triangle is given by: Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} Here, the base of the triangle is the horizontal leg (let's call it b), and the height is h.

To find b, we use the cosine function: cos(𝜃)=adjacenthypotenuse=bx\cos(𝜃) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{b}{x} Thus: b=xcos(𝜃)b = x \cos(𝜃) Once we have b, we can compute the area: Area=12×b×h\text{Area} = \frac{1}{2} \times b \times h

Let’s calculate b and the area.### Results:

(a) The length of the rafter (x) is approximately 63.1ft63.1 \, \text{ft}.

(b) The area of the gable is approximately 878.9ft2878.9 \, \text{ft}^2.

Do you need more details, or have any other questions?

Here are some related questions you might consider:

  1. How would the value of x change if the angle 𝜃 increased?
  2. What is the relationship between the height h and the area of the gable?
  3. Can you calculate the perimeter of the gable triangle?
  4. What is the formula for the area of a triangle in general?
  5. How would the area change if the height h were doubled?

Tip: When working with right triangles, always consider the sine, cosine, or tangent functions based on the sides and angle you have.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Geometry
Right Triangles

Formulas

sin(𝜃) = h / x
cos(𝜃) = b / x
Area = (1/2) × base × height

Theorems

Trigonometric functions for right triangles
Area of a triangle

Suitable Grade Level

Grades 9-12