How would you find out the x? (x$$ ^2 $$-1) = 0

To find $ x $ in the equation:

\[
x^2 - 1 = 0
\]

we can solve it step by step:

1. **Add 1 to both sides of the equation**:
   \[
   x^2 - 1 + 1 = 0 + 1
   \]
   This simplifies to:
   \[
   x^2 = 1
   \]

2. **Take the square root of both sides**:
   \[
   \sqrt{x^2} = \pm \sqrt{1}
   \]
   So, $ x = \pm 1 $.

Thus, the solutions are $ x = 1 $ and $ x = -1 $.

Would you like more details on this process or have any questions?

Here are 5 related questions to deepen your understanding:

1. How would you solve $ x^2 - 4 = 0 $?
2. What happens if the equation was $ x^2 + 1 = 0 $?
3. How do you solve quadratic equations when they are not factorable?
4. Can you solve $ x^2 - 9 = 0 $ by factoring?
5. How would you solve a cubic equation like $ x^3 - 1 = 0 $?

**Tip**: Always remember to check for both the positive and negative roots when solving $ x^2 = c $ equations.

How would you find out the x? (x^2 - 1) = 0

Learn how to solve the quadratic equation x^2 - 1 = 0 by applying basic algebraic steps. This solution uses key concepts like square roots and the Zero Product Property. Suitable for students in Grades 7-9.

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