Math Problem Statement

Solve x:x^2-2x+1=0

Solution

To solve the equation:

x22x+1=0x^2 - 2x + 1 = 0

Step 1: Factoring the equation

Notice that the quadratic expression can be factored:

x22x+1=(x1)2x^2 - 2x + 1 = (x - 1)^2

Thus, the equation is equivalent to:

(x1)2=0(x - 1)^2 = 0

Step 2: Solve for x

To solve (x1)2=0(x - 1)^2 = 0, take the square root of both sides:

x1=0x - 1 = 0

So:

x=1x = 1

Solution

The solution to the equation is:

x=1x = 1

Would you like more details on the factoring process or have any other questions? Here are five related questions to deepen your understanding:

  1. What is the general method for factoring quadratic equations?
  2. How can the quadratic formula be used to solve x22x+1=0x^2 - 2x + 1 = 0?
  3. What does it mean when a quadratic equation has a "double root"?
  4. How do you determine the number of solutions a quadratic equation has?
  5. What are some real-life applications of solving quadratic equations?

Tip: If the discriminant of a quadratic equation (b24acb^2 - 4ac) is zero, it indicates the equation has a double root. This means there is exactly one solution, but it's counted twice.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factoring

Formulas

Quadratic equation formula ax^2 + bx + c = 0

Theorems

Zero Product Property
Factoring of Perfect Square Trinomials

Suitable Grade Level

Grades 7-9