solve the algebraic expression 3x3y−5x2y3*x*3*y*−5*x*2*y* for x=−2*x*=−2 and y=−1*y*=−1

We are asked to solve the algebraic expression \( 3x^3y - 5x^2y^3 \) for \( x = -2 \) and \( y = -1 \).

### Step-by-Step Solution

1. The given expression is:
   \[
   3x^3y - 5x^2y^3
   \]

2. Substitute \( x = -2 \) and \( y = -1 \) into the expression.

   - For the first term \( 3x^3y \):
     \[
     3(-2)^3(-1) = 3(-8)(-1) = 24
     \]

   - For the second term \( -5x^2y^3 \):
     \[
     -5(-2)^2(-1)^3 = -5(4)(-1) = 20
     \]

3. Now, subtract the second term from the first:
   \[
   24 + 20 = 44
   \]

### Final Answer:
The value of the expression \( 3x^3y - 5x^2y^3 \) when \( x = -2 \) and \( y = -1 \) is **44**.

Would you like more details or have any questions?

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Here are 5 related questions to expand your understanding:

1. What happens to the expression if \( x = 2 \) and \( y = 1 \)?
2. Can you generalize how changing the sign of \( y \) affects the final result?
3. How would you factor this expression before substitution?
4. What is the impact of increasing the powers of \( x \) or \( y \) in each term?
5. How does solving algebraic expressions change when additional variables are introduced?

**Tip:** Always perform substitutions carefully, especially when dealing with negative numbers to avoid sign errors.

Solve the algebraic expression 3x^3y - 5x^2y^3 for x = -2 and y = -1.

Learn how to solve the polynomial expression 3x^3y - 5x^2y^3 by substituting values x = -2 and y = -1. This step-by-step solution covers key algebraic concepts like exponentiation and substitution, ideal for students in Grades 9-10.

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