Math Problem Statement

Solve all the questions

Solve all the questions

Solution

Here are solutions for each of the questions visible in the uploaded image:


Question 28

Problem:
If 34\frac{3}{4} of 13\frac{1}{3} of 15\frac{1}{5} of a number is 25, what is the number?

Solution:
Let the number be xx. Then: 341315x=25\frac{3}{4} \cdot \frac{1}{3} \cdot \frac{1}{5} \cdot x = 25 Simplify the left-hand side: 120x=25\frac{1}{20} \cdot x = 25 Multiply both sides by 20: x=500x = 500 Answer: (D) 500


Question 29

Problem:
Find the remainder when 1720017^{200} is divided by 18.

Solution:
Using Fermat's Little Theorem: a^{p-1} \equiv 1 \mod p \text{ (when aandandp are coprime)} Here, 1717 and 1818 are coprime. Since p=18p = 18, 17ϕ(18)1mod1817^{\phi(18)} \equiv 1 \mod 18.
ϕ(18)=6\phi(18) = 6, so 1761mod1817^6 \equiv 1 \mod 18.

Now, divide 200200 by 66: 200=6×33+2200 = 6 \times 33 + 2 Thus, 17200172mod1817^{200} \equiv 17^2 \mod 18. Calculate 172mod1817^2 \mod 18: 172=289and289÷18=16 remainder 117^2 = 289 \quad \text{and} \quad 289 \div 18 = 16 \text{ remainder } 1 So, the remainder is 11.

Answer: (A) 1


Question 30

Problem:
A number, when divided by 296, leaves a remainder of 75. When the same number is divided by 37, what is the remainder?

Solution:
Using modular arithmetic: x75mod296x \equiv 75 \mod 296 We know 296=37×8296 = 37 \times 8. Since xx modulo 296 also satisfies modulo 37: 75÷37=2 remainder 175 \div 37 = 2 \text{ remainder } 1 So, the remainder is 11.

Answer: (A) 1


Question 31

Problem:
When a natural number nn is divided by 4, the remainder is 3. What is the remainder when 2n2n is divided by 4?

Solution:
If n3mod4n \equiv 3 \mod 4, then: 2n23mod42n \equiv 2 \cdot 3 \mod 4 2n6mod46÷4=1 remainder 22n \equiv 6 \mod 4 \quad \Rightarrow \quad 6 \div 4 = 1 \text{ remainder } 2 So, the remainder is 22.

Answer: (B) 2


Question 32

Problem:
A man traveled 211\frac{2}{11} of his journey by coach, 711\frac{7}{11} by rail, and walked the remaining 1 km. How far did he go?

Solution:
Let the total distance be xx. Then: 211x+711x+1=x\frac{2}{11}x + \frac{7}{11}x + 1 = x Simplify: 911x+1=x\frac{9}{11}x + 1 = x 1=211xx=112×1=111 = \frac{2}{11}x \quad \Rightarrow \quad x = \frac{11}{2} \times 1 = 11 The total distance is 1111 km.

Answer: (A) 22 km


Question 33

Problem:
A boy was asked to multiply a number by 53. By mistake, he multiplied it by 35. If his answer was 1206 less than the correct one, find the number.

Solution:
Let the number be xx. The equation is: 53x35x=120653x - 35x = 1206 Simplify: 18x=1206x=120618=6718x = 1206 \quad \Rightarrow \quad x = \frac{1206}{18} = 67 Answer: (B) 67


Summary of Answers:

  1. (D) 500
  2. (A) 1
  3. (A) 1
  4. (B) 2
  5. (A) 22 km
  6. (B) 67

Would you like me to explain any of the solutions in more detail?
Here are five related questions to extend your understanding:

  1. What is Fermat's Little Theorem and how is it used in modular arithmetic problems?
  2. How do you simplify fractional equations like in Question 28?
  3. Why is modular arithmetic useful in remainder problems like Question 30?
  4. Can you generalize the steps for solving problems like Question 32?
  5. What are practical tips to avoid mistakes in word-based arithmetic problems?

Tip: Always verify the final step of your calculations, especially when working with modular arithmetic!

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Math Problem Analysis

Mathematical Concepts

Modular Arithmetic
Fractional Equations
Linear Equations
Word Problems
Number Theory

Formulas

Fermat's Little Theorem: a^(p-1) ≡ 1 (mod p)
Modular Arithmetic: x ≡ a (mod m)
Linear Equation: ax + b = c

Theorems

Fermat's Little Theorem
Chinese Remainder Theorem

Suitable Grade Level

Grades 9-12