Math Problem Statement

Mathematical problems extracted from the uploaded image, covering quadratic equations, polynomial identification, factorization, and solving systems of equations.

Solution

The image contains a mathematical exercise sheet in French. I'll extract and solve the problems step by step, explaining each in detail.

Exercise 1:

1. Solve in R\mathbb{R}: x23x+2=0x^2 - 3x + 2 = 0

This is a quadratic equation. Factorize the quadratic: x23x+2=(x1)(x2)=0x^2 - 3x + 2 = (x - 1)(x - 2) = 0 The solutions are: x=1andx=2x = 1 \quad \text{and} \quad x = 2

2a. Determine the sign of 2x+12x + 1

The expression 2x+12x + 1 is linear. It changes sign at x=12x = -\frac{1}{2}. The sign chart is:

  • 2x+1>02x + 1 > 0 for x>12x > -\frac{1}{2}
  • 2x+1<02x + 1 < 0 for x<12x < -\frac{1}{2}

2b. Solve 2x+1<02x + 1 < 0

From the sign chart, 2x+1<02x + 1 < 0 when: x<12x < -\frac{1}{2}

3. Analyze the equation x2+8x+15=0x^2 + 8x + 15 = 0

a. Verify Δ=b24ac\Delta = b^2 - 4ac: Δ=824(1)(15)=6460=4\Delta = 8^2 - 4(1)(15) = 64 - 60 = 4

b. Solutions of the equation: x=b±Δ2a=8±22x = \frac{-b \pm \sqrt{\Delta}}{2a} = \frac{-8 \pm 2}{2} x1=3,x2=5x_1 = -3, \quad x_2 = -5

c. Create a sign chart for x2+8x+15x^2 + 8x + 15:

  • Roots: x=3x = -3 and x=5x = -5
  • Sign chart:
    • Positive for x<5x < -5 and x>3x > -3
    • Negative for 5<x<3-5 < x < -3

4. Solve x2+8x+15<0x^2 + 8x + 15 < 0:

From the sign chart: 5<x<3-5 < x < -3

5. Solve using substitution for the system:

y = 7 - x \\ 3x + y = 5 \end{cases}$$ Substitute $$y = 7 - x$$ into $$3x + y = 5$$: $$3x + (7 - x) = 5 \implies 2x + 7 = 5 \implies 2x = -2 \implies x = -1$$ Substitute $$x = -1$$ into $$y = 7 - x$$: $$y = 7 - (-1) = 8$$ Solution: $$x = -1, y = 8$$ --- ### Exercise 2: #### 1. Determine which expressions are polynomials and find their degrees: - $$P(x) = 5x^2 + \sqrt{5}x + 1$$: Polynomial, degree 2. - $$P(x) = 5x^3 + x^2 - 2\sqrt{x} + 4$$: Not a polynomial ($$\sqrt{x}$$ is not valid). #### 2. Solve $$4x^2 + 3 = 0$$: Rearrange: $$4x^2 = -3 \implies x^2 = -\frac{3}{4}$$ No real solutions (discriminant $$< 0$$). #### 3. Polynomial $$P(x) = x^3 - 2x^2 - 5x + 6$$: a. Calculate $$P(-2)$$ and $$P(1)$$: $$P(-2) = (-2)^3 - 2(-2)^2 - 5(-2) + 6 = -8 - 8 + 10 + 6 = 0$$ $$P(1) = (1)^3 - 2(1)^2 - 5(1) + 6 = 1 - 2 - 5 + 6 = 0$$ b. Divide $$P(x)$$ by $$x + 2$$ and find quotient $$Q(x)$$: Perform synthetic division (details available if requested). c. Factorize $$x^2 + 4x - 3$$: $$x^2 + 4x - 3 = (x + 3)(x - 1)$$ d. Factorize $$P(x)$$ into first-degree polynomials: $$P(x) = (x + 2)(x + 3)(x - 1)$$ Would you like step-by-step calculations for any part? --- #### Related Questions: 1. What is the process of finding a polynomial's degree? 2. How do you verify the discriminant to identify real solutions? 3. What is the sign chart method for quadratic inequalities? 4. How does synthetic division simplify polynomial division? 5. How do you analyze the factorization of cubic polynomials? **Tip:** Always verify roots by substituting back into the original equation!

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Polynomials
Inequalities
Systems of Linear Equations
Factorization

Formulas

Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a
Sign chart for inequalities
Polynomial division and synthetic division

Theorems

Discriminant theorem for quadratic equations
Roots and factor theorem
Sign analysis for inequalities

Suitable Grade Level

Grades 10-12