Math Problem Statement

⁵logaritma25. ²⁵logaritma625

Solution

Let's break down the logarithmic expressions you provided:

  1. log525\log_5{25}

This is asking, "To what power must 5 be raised to give 25?" We know: 52=255^2 = 25 Thus: log525=2\log_5{25} = 2

  1. log25625\log_{25}{625}

This is asking, "To what power must 25 be raised to give 625?" Now, remember that: 25=52and625=5425 = 5^2 \quad \text{and} \quad 625 = 5^4 Thus, this can be rewritten as: log25625=log5254\log_{25}{625} = \log_{5^2}{5^4} Using the change of base property: logambn=nm\log_{a^m}{b^n} = \frac{n}{m} We get: log5254=42=2\log_{5^2}{5^4} = \frac{4}{2} = 2

So, log25625=2\log_{25}{625} = 2.

Final Results:

  1. log525=2\log_5{25} = 2
  2. log25625=2\log_{25}{625} = 2

Would you like any more details or clarifications?

Here are 5 related questions:

  1. How do you change the base of a logarithm?
  2. What is log327\log_3{27}?
  3. What is the relationship between exponential and logarithmic functions?
  4. How do logarithmic properties simplify calculations?
  5. How can we solve logarithmic equations?

Tip: Always check if the bases of the logarithms can be expressed as powers of smaller numbers—it can simplify the calculations!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponents
Change of Base

Formulas

\log_b{a} = c \text{ if } b^c = a
Change of base formula: \log_{a^m}{b^n} = \frac{n}{m}

Theorems

Logarithmic properties
Change of Base Theorem

Suitable Grade Level

Grades 10-12