The image contains five logarithmic expressions, and I'll help solve them step by step. Let's start by simplifying each of the logarithmic equations one by one.
1. 2log18+2log6−2log27
This can be simplified using the logarithmic properties:
- 2loga+2logb=2log(a⋅b)
- 2loga−2logb=2log(ba)
Applying this:
2log(18⋅6)−2log27=2log(2718⋅6)
2log(27108)=2log4
So, the expression simplifies to 2log4=2.
2. 3log72−2⋅3log4+3log2
Again using the properties:
- n⋅bloga=blog(an)
- bloga−blogb=blog(ba)
Simplifying step by step:
3log72−2⋅3log4+3log2=3log72−3log(42)+3log2
=3log72−3log16+3log2=3log(1672⋅2)
=3log(16144)=3log9
So, the expression simplifies to 3log9=2.
3. log300+2⋅log3−log0.27
Simplifying the terms:
2⋅log3=log32=log9
Using the property:
loga+logb=log(a⋅b),loga−logb=log(ba)
log300+log9−log0.27=log(0.27300⋅9)
=log(0.272700)=log10000
Thus, the result is log10000=4.
4. 2log16−3log271+5log1
Simplifying:
- blog1=0 (logarithm of 1 is always 0)
- bloga−1=−bloga
So:
2log16−3log271+5log1=2log16+3log27+0
Since 2log16=4 and 3log27=3, the expression becomes:
4+3=7
5. log24−2⋅log2+log61
Simplifying:
2⋅log2=log22=log4
Using logarithmic properties:
log24−log4+log61=log(424)+log61
=log6+log61=log(6⋅61)
=log1=0
Thus, the expression simplifies to 0.
Summary of Results:
- 2
- 2
- 4
- 7
- 0
Would you like more details on any of these solutions?
Related Questions:
- What are the basic properties of logarithms?
- How do logarithmic functions relate to exponential functions?
- What are common mistakes made when simplifying logarithmic expressions?
- How do you apply logarithmic transformations in real-world problems?
- What are the different bases commonly used in logarithms (e.g., natural log, base-10 log)?
Tip:
Remember that the logarithmic identities loga+logb=log(ab) and loga−logb=log(ba) are your best tools for simplifying expressions.