The image shows the logarithmic equation:
$\log_5 (3x + 4) = 2$ To solve this, follow these steps:

1. Rewrite the equation in exponential form: $5^2 = 3x + 4$ Since the base of the logarithm is 5, the equation becomes $5^2$ on the left side.

2. Simplify: $25 = 3x + 4$

3. Isolate the variable: $25 - 4 = 3x$ $21 = 3x$

4. Solve for $x$: $x = \frac{21}{3}$ $x = 7$

Thus, the solution is $x = 7$.

Would you like further explanation or have any questions about logarithms?

Here are 5 related questions:

1. How do you convert between logarithmic and exponential forms?
2. What happens if the logarithmic equation has a different base, like $\log_2$?
3. How do you solve logarithmic equations with multiple terms inside the log?
4. What is the property of logarithms that allows you to combine terms like $\log_b(x) + \log_b(y)$?
5. How can you check the solution to a logarithmic equation?

Tip: Always check the domain of the logarithmic function before solving. The expression inside the logarithm must be positive!