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To solve the equation \( \log_2(3 - 5x) = 3 \):

1. **Rewrite the logarithmic equation in exponential form**:
   \[
   3 - 5x = 2^3
   \]

2. **Calculate \( 2^3 \)**:
   \[
   2^3 = 8
   \]
   So, the equation becomes:
   \[
   3 - 5x = 8
   \]

3. **Isolate \( x \)**:
   Subtract 3 from both sides:
   \[
   -5x = 8 - 3
   \]
   \[
   -5x = 5
   \]

4. **Solve for \( x \)** by dividing both sides by -5:
   \[
   x = \frac{5}{-5} = -1
   \]

### Solution:
\[
x = -1
\]

Would you like further explanation on logarithmic or exponential equations?

Here are some additional questions to explore:
1. What are the basic properties of logarithms?
2. How can logarithmic equations be applied in real-world problems?
3. What is the inverse function of a logarithmic function?
4. How do you solve logarithmic equations with different bases?
5. How can you verify the solution to a logarithmic equation?

**Tip:** Always check the domain of the logarithmic function to ensure your solution makes the argument of the logarithm positive.

Step-by-step solution for solving the logarithmic equation log2(3 - 5x) = 3. Learn how to convert logarithmic form to exponential form and isolate the variable x. Suitable for students in Grades 9-10.

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