The problem asks for the solution to the equation:

$\log_2(9x) - \log_2 3 = 3$

Let's solve this step by step:

Step 1: Apply the logarithmic property

Using the property of logarithms:

$\log_b A - \log_b B = \log_b \left(\frac{A}{B}\right)$

This simplifies the equation as follows:

$\log_2 \left(\frac{9x}{3}\right) = 3$

Step 2: Simplify the fraction

Simplify the expression inside the logarithm:

$\frac{9x}{3} = 3x$

Now the equation becomes:

$\log_2(3x) = 3$

Step 3: Eliminate the logarithm

To eliminate the logarithm, we rewrite the equation in exponential form:

$3x = 2^3$

Simplifying $2^3 = 8$, we get:

$3x = 8$

Step 4: Solve for $x$

$x = \frac{8}{3}$

Thus, the solution is:

$x = \frac{8}{3}$

The correct answer is $\boxed{x = \frac{8}{3}}$.

Would you like more details on any of these steps? Here are five related questions to consider:

1. How do logarithmic properties help in simplifying equations?
2. What is the process of converting a logarithmic equation to an exponential one?
3. Why is it important to apply the correct logarithmic rules in equations like this?
4. How can we verify the solution by substituting $x = \frac{8}{3}$ back into the original equation?
5. What are some common mistakes to avoid when dealing with logarithmic equations?

Tip: Always remember that logarithmic subtraction can be transformed into a division inside a single logarithm.