To solve the equation

$\log_2 (x - 3) = \log_2 9$

we can proceed as follows:

1. Since both sides of the equation have the same base (base 2), we can remove the logarithms and set the arguments equal to each other. This gives: $x - 3 = 9$

2. Solving for $x$, we add 3 to both sides: $x = 9 + 3 = 12$

Therefore, the solution is: $x = 12$

Would you like further details or have any questions?

Here are some related questions for further practice:

1. Solve $\log_5 (x + 4) = \log_5 16$.
2. Solve $\log_3 (2x + 1) = \log_3 7$.
3. Solve $\log_4 (x - 2) = \log_4 25$.
4. If $\log_7 (x - 5) = \log_7 11$, what is $x$?
5. Solve $\log_8 (3x - 4) = \log_8 10$.

Tip: When solving equations with logarithms of the same base, you can equate the arguments directly if the logs are isolated on both sides.