Math Problem Statement

Solve for x: log_10(3x) = 5.7. The user provided the solution as x = 1.9 (rounded to two decimal places).

Solution

The equation displayed is:

log10(3x)=5.7\log_{10}(3x) = 5.7

Steps to Solve:

  1. Rewrite the logarithmic equation in exponential form: 3x=105.73x = 10^{5.7}

  2. Calculate 105.710^{5.7}: 105.7=501187.233610^{5.7} = 501187.2336

  3. Solve for xx: Divide both sides by 3: x=501187.23363=167062.4112x = \frac{501187.2336}{3} = 167062.4112

  4. Round to the required decimal places: Rounding xx to two decimal places: x=167062.41x = 167062.41

It seems the given solution (x=1.9x = 1.9) is incorrect based on this calculation. If you would like, I can re-check or explore further details to verify! Let me know.


Questions for further exploration:

  1. Would you like me to verify using a different logarithmic base or calculator?
  2. Should I re-check your original solution using alternative methods?
  3. Do you want a graph representation of this equation?
  4. Can I help you understand how logarithmic and exponential relationships work in depth?
  5. Would you like to explore how this relates to real-world problems?

Tip: Always double-check base conversions in logarithmic problems, as mistakes in the base or rounding can lead to incorrect results.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Equations

Formulas

log_b(a) = c implies a = b^c

Theorems

Logarithmic-Exponential Relationship

Suitable Grade Level

Grades 10-12