The equation provided is:

$\log_3 x = 5$

To solve for $x$, we need to rewrite this logarithmic equation in its exponential form. The general form of a logarithmic equation is:

$\log_b y = z \quad \text{which is equivalent to} \quad y = b^z$

In this case:

$\log_3 x = 5 \quad \text{is equivalent to} \quad x = 3^5$

Now, calculate $3^5$:

$3^5 = 3 \times 3 \times 3 \times 3 \times 3 = 243$

Thus, the value of $x$ is:

$x = 243$

Would you like more details or have any questions?

Here are some related questions to explore:

1. How do you convert between logarithmic and exponential forms?
2. What are the properties of logarithms that can simplify solving equations?
3. How does changing the base of the logarithm affect the result?
4. How can you use a calculator to solve logarithmic equations with different bases?
5. What is the meaning of logarithmic scales in real-world applications?

Tip: When solving logarithmic equations, always remember that you can switch to the exponential form for easier calculation.