Math Problem Statement

Solve for x: ln(x) - ln(4) = 0

Solution

The equation provided is:

ln(x)ln(4)=0\ln(x) - \ln(4) = 0

To solve for xx:

Step 1: Simplify the equation

Using the logarithmic property ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right), the equation becomes: ln(x4)=0\ln\left(\frac{x}{4}\right) = 0

Step 2: Exponentiate to eliminate the logarithm

Exponentiate both sides of the equation with base ee: x4=e0\frac{x}{4} = e^0 Since e0=1e^0 = 1: x4=1\frac{x}{4} = 1

Step 3: Solve for xx

Multiply both sides by 4: x=4x = 4

Final Answer:

x=4x = 4

Would you like me to explain any step in more detail or provide additional related problems to practice? Here are some related questions to expand your understanding:

  1. What is the general property of logarithms for subtraction, and how does it apply to different bases?
  2. How would the solution change if the equation were ln(x)ln(a)=0\ln(x) - \ln(a) = 0 for some arbitrary aa?
  3. Can logarithmic equations like this have no solution or multiple solutions? Why or why not?
  4. How would you graph ln(x)ln(4)\ln(x) - \ln(4) and verify the solution visually?
  5. What happens if you replace ln\ln with log\log (logarithm base 10) in the equation?

Tip: Always check the domain of the logarithmic functions to ensure the arguments are valid (positive numbers).

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Math Problem Analysis

Mathematical Concepts

Logarithms
Simplification of logarithmic expressions

Formulas

ln(a) - ln(b) = ln(a/b)
e^x (exponentiation to eliminate logarithms)

Theorems

Logarithmic properties (difference of logarithms)
Exponential functions

Suitable Grade Level

Grades 9-12