Math Problem Statement

Solve the logarithmic equation algebraically. Approximate the result to three decimal places. (If there is no solution, enter NO SOLUTION.) ln(x + 1) − ln(x − 4) = ln(x)

Solution

To solve the equation ln(x+1)ln(x4)=ln(x)\ln(x + 1) - \ln(x - 4) = \ln(x) algebraically, we’ll start by applying logarithmic properties.

Step 1: Use the Quotient Rule

The equation can be rewritten using the quotient rule for logarithms: ln(x+1x4)=ln(x)\ln\left(\frac{x + 1}{x - 4}\right) = \ln(x)

Step 2: Eliminate the Logarithms

Since we have ln(x+1x4)=ln(x)\ln\left(\frac{x + 1}{x - 4}\right) = \ln(x), we can exponentiate both sides to remove the logarithms: x+1x4=x\frac{x + 1}{x - 4} = x

Step 3: Multiply Both Sides by x4x - 4

To clear the fraction, multiply both sides by x4x - 4: x+1=x(x4)x + 1 = x(x - 4) Expanding the right side: x+1=x24xx + 1 = x^2 - 4x

Step 4: Rearrange into a Quadratic Equation

Bring all terms to one side of the equation to set it equal to zero: 0=x25x10 = x^2 - 5x - 1

Step 5: Solve the Quadratic Equation

The equation x25x1=0x^2 - 5x - 1 = 0 is a quadratic equation that can be solved using the quadratic formula: x=(5)±(5)241(1)21x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 1 \cdot (-1)}}{2 \cdot 1} x=5±25+42x = \frac{5 \pm \sqrt{25 + 4}}{2} x=5±292x = \frac{5 \pm \sqrt{29}}{2}

Step 6: Simplify and Approximate

Calculating the two possible values for xx: x=5+2925.192x = \frac{5 + \sqrt{29}}{2} \approx 5.192 x=52920.192x = \frac{5 - \sqrt{29}}{2} \approx -0.192

Step 7: Check for Extraneous Solutions

Since we are dealing with logarithms, the arguments must be positive. Therefore, we need x>4x > 4 for ln(x4)\ln(x - 4) to be defined.

  • The solution x5.192x \approx 5.192 is valid since it is greater than 4.
  • The solution x0.192x \approx -0.192 is not valid because it does not satisfy the domain restrictions.

Final Answer

The solution is: x5.192x \approx 5.192

Let me know if you need further details or have any questions!


  1. What are the steps to solving logarithmic equations involving the quotient rule?
  2. How can extraneous solutions occur in logarithmic equations?
  3. Why is the quadratic formula useful in solving quadratic equations?
  4. How can logarithmic properties simplify equations?
  5. What domain restrictions are commonly applied in logarithmic functions?

Tip: Always check for domain restrictions when solving logarithmic equations to avoid extraneous solutions.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Equations
Logarithmic Properties
Quadratic Equations

Formulas

Logarithmic Quotient Rule
Quadratic Formula

Theorems

Logarithmic Properties
Quadratic Formula

Suitable Grade Level

Grades 9-12