We are tasked with finding an inequality to represent the number of hours $x$ when the tank contains less water than the pool.

Step-by-step breakdown:

1. Water in the tank after $x$ hours:

   • Initially, the tank contains 1,375 gallons.
   • Every hour, 28 gallons of water leaks from the tank, so after $x$ hours, the amount of water lost from the tank is $28x$.
   • Therefore, the amount of water in the tank after $x$ hours is $1,375 - 28x$.

2. Water in the pool after $x$ hours:

   • The pool starts empty, and water is added at a rate of 560 gallons per hour.
   • So, after $x$ hours, the amount of water in the pool is $560x$.

3. Set up the inequality:

   • We want to find when the water in the tank is less than the water in the pool, which means we need to set up the inequality: $1,375 - 28x < 560x$

Thus, the correct inequality is:

$\boxed{C. \, 1,375 - 28x < 560x}$

Do you want further details on solving or interpreting this inequality?

Here are 5 related questions to explore:

1. What happens to the tank's water level after a given number of hours?
2. How would the equation change if the leak rate increases?
3. What if the pool filled at a slower rate—how would that affect the inequality?
4. How long will it take until both the tank and pool have the same amount of water?
5. What if the tank starts with less water—how does that change the inequality?

Tip: When solving inequalities, remember to keep the inequality direction consistent when dividing or multiplying both sides by a positive number.