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**III. Math Problem (10 points)**

A tank initially contains 300 liters of water. It loses 20 liters of water per minute and has a valve at the bottom that is gradually letting in 5 liters per minute. The total amount of water in the tank at any given time is given by the formula:  
\[ W(t) = 300 - 20t + 5t \]

1. Explain why the formula is written this way.
2. Describe what each part of the formula represents.
3. When will the tank be empty?
4. Verify the formula by checking the value for \( t = 0 \), \( t = 10 \), and \( t = 20 \).

**Instructions:** Answer all questions completely and show your work.

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A tank initially contains 300 liters of water. It loses 20 liters of water per minute and has a valve at the bottom that is gradually letting in 5 liters per minute. The total amount of water in the tank at any given time is given by the formula: W(t) = 300 - 20t + 5t. The problem asks to explain why the formula is written this way, describe what each part of the formula represents, determine when the tank will be empty, and verify the formula by checking the value for t = 0, t = 10, and t = 20.

Understand how to solve a linear equation involving a water tank losing and gaining water at different rates. This example covers key mathematical concepts like linear equations and rates of change, suitable for students in Grades 6-8.

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