Let's break down the problem step by step:

We are given that:

• The sum of a number and 2 is 6 less than twice that number.

Let the unknown number be $x$.

Step 1: Translate the problem into an equation.

• "The sum of a number and 2" means $x + 2$.
• "6 less than twice that number" means $2x - 6$.

According to the problem, these two expressions are equal. So, we write the equation: $x + 2 = 2x - 6$

Step 2: Solve the equation.

1. Subtract $x$ from both sides to get the variables on one side: $2 = x - 6$

2. Add 6 to both sides to isolate $x$: $8 = x$

Final Answer:

The number is $x = 8$.

Would you like more details, or have any questions?

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Here are 5 related questions to expand your understanding:

1. What would happen if the number was 3 less than twice the number instead of 6 less?
2. How would you represent "the difference between a number and 5 is equal to twice the number" as an equation?
3. What if the sum of a number and 5 is equal to 10 less than three times that number?
4. How do you solve $3x + 7 = 2x - 9$?
5. How can you check if your solution is correct for a given equation?

Tip: Always verify your solution by substituting it back into the original equation to ensure both sides are equal!