The sum of a number and 2 is 6 less than twice that number.

Let's break down the problem step by step:

We are given that:
- The sum of a number and 2 is 6 less than twice that number.

Let the unknown number be \( x \).

### Step 1: Translate the problem into an equation.

- "The sum of a number and 2" means \( x + 2 \).
- "6 less than twice that number" means \( 2x - 6 \).

According to the problem, these two expressions are equal. So, we write the equation:
\[
x + 2 = 2x - 6
\]

### Step 2: Solve the equation.

1. Subtract \( x \) from both sides to get the variables on one side:
\[
2 = x - 6
\]

2. Add 6 to both sides to isolate \( x \):
\[
8 = x
\]

### Final Answer:
The number is \( x = 8 \).

Would you like more details, or have any questions?

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Here are 5 related questions to expand your understanding:
1. What would happen if the number was 3 less than twice the number instead of 6 less?
2. How would you represent "the difference between a number and 5 is equal to twice the number" as an equation?
3. What if the sum of a number and 5 is equal to 10 less than three times that number?
4. How do you solve \( 3x + 7 = 2x - 9 \)?
5. How can you check if your solution is correct for a given equation?

**Tip**: Always verify your solution by substituting it back into the original equation to ensure both sides are equal!

Learn how to solve a linear equation where the sum of a number and 2 equals 6 less than twice the number. This step-by-step solution is suitable for students in Grades 6-8 and covers key algebraic concepts.

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