Math Problem Statement

A movie theater has a seating capacity of 303. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. There are half as many adults as there are children. If the total ticket sales was $2208, how many children, students, and adults attended?

Solution

Let's solve this problem step-by-step using algebra.

Step 1: Define the variables

Let:

  • CC be the number of children.
  • SS be the number of students.
  • AA be the number of adults.

Step 2: Write the equations based on the problem conditions

  1. Total number of attendees equation: C+S+A=303C + S + A = 303

  2. Relationship between the number of children and adults: A=12CA = \frac{1}{2}C

  3. Total ticket sales equation: 5C+7S+12A=22085C + 7S + 12A = 2208

Step 3: Substitute the relationship A=12CA = \frac{1}{2}C into the equations

Substituting A=12CA = \frac{1}{2}C into the total number of attendees equation: C+S+12C=303C + S + \frac{1}{2}C = 303 Multiplying the entire equation by 2 to clear the fraction: 2C+2S+C=6062C + 2S + C = 606 3C+2S=606(Equation 1)3C + 2S = 606 \quad \text{(Equation 1)}

Substituting A=12CA = \frac{1}{2}C into the ticket sales equation: 5C+7S+12(12C)=22085C + 7S + 12\left(\frac{1}{2}C\right) = 2208 5C+7S+6C=22085C + 7S + 6C = 2208 11C+7S=2208(Equation 2)11C + 7S = 2208 \quad \text{(Equation 2)}

Step 4: Solve the system of equations

We now have the following system of equations:

  1. 3C+2S=6063C + 2S = 606
  2. 11C+7S=220811C + 7S = 2208

Let's solve these equations using elimination or substitution. I'll proceed with elimination for clarity.

Multiply Equation 1 by 7 to align with the second equation: 21C+14S=424221C + 14S = 4242

Multiply Equation 2 by 2 to align with the first equation: 22C+14S=441622C + 14S = 4416

Subtract the first modified equation from the second: (22C+14S)(21C+14S)=44164242(22C + 14S) - (21C + 14S) = 4416 - 4242 C=174C = 174

Step 5: Substitute C=174C = 174 back into Equation 1

3(174)+2S=6063(174) + 2S = 606 522+2S=606522 + 2S = 606 2S=842S = 84 S=42S = 42

Step 6: Find the number of adults using A=12CA = \frac{1}{2}C

A=12(174)=87A = \frac{1}{2}(174) = 87

Final Answer

  • Number of children (C): 174
  • Number of students (S): 42
  • Number of adults (A): 87

Would you like more details on any of these steps, or do you have any questions?

Here are some related questions to expand on this problem:

  1. What would be the new total ticket sales if the price for adults was increased to $15?
  2. How would the distribution change if the total seating capacity increased to 350?
  3. What happens to the number of students if the total number of adults becomes one-third of the children?
  4. If the theater gave a discount of $2 for each category, how much would the total ticket sales be?
  5. Can this problem be solved using matrix methods or a different algebraic approach?

Tip: In word problems, clearly defining variables and writing equations step-by-step makes it easier to organize information and find solutions.

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Math Problem Analysis

Mathematical Concepts

Algebra
System of Linear Equations

Formulas

C + S + A = 303
A = 1/2C
5C + 7S + 12A = 2208

Theorems

Linear System Solving

Suitable Grade Level

Grades 8-10