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Let's break down the problem and solve it step by step.

We are given:
- Child admission price: $5.40
- Adult admission price: $9.40
- Total tickets sold: 156
- Total sales: $1090.40

We need to find how many child tickets were sold. Let:
- $ x $ = number of child tickets sold
- $ y $ = number of adult tickets sold

We have two key equations:
1. The total number of tickets sold:  
   $ x + y = 156 $
   
2. The total sales equation:  
   $ 5.40x + 9.40y = 1090.40 $

We can solve this system of equations by substitution or elimination. I will solve it now.The solution to the system of equations shows that 94 child tickets and 62 adult tickets were sold that day.

Would you like more details on how the solution was derived or any further assistance?

Here are 5 related questions you might find interesting:
1. What if the total sales had been $1200, keeping the same ticket prices?
2. How would the result change if the number of adult tickets sold was known?
3. Can you derive the formula for the number of child tickets directly from the given data?
4. What happens if the child and adult ticket prices are swapped?
5. How many child tickets would need to be sold for the total sales to reach $1500?

**Tip:** When solving a system of equations, always check your results by substituting the solution back into the original equations to verify accuracy.

At the city museum, child admission is $5.40 and adult admission is $9.40. On Friday, 156 tickets were sold for a total sales of $1090.40. How many child tickets were sold that day?

Learn how to solve a system of linear equations to find the number of child and adult tickets sold at a museum. The problem involves algebraic concepts with two variables and equations based on ticket prices and total sales.

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