To solve the equation \( a = 9y + 3yx \) for \( y \), follow these steps:

1. **Factor the right-hand side**: Notice that \( y \) is a common factor in both terms on the right-hand side.
   \[
   a = y(9 + 3x)
   \]

2. **Isolate \( y \)**: Divide both sides of the equation by \( (9 + 3x) \) to solve for \( y \).
   \[
   y = \frac{a}{9 + 3x}
   \]

Thus, the solution for \( y \) is:
\[
y = \frac{a}{9 + 3x}
\]

Would you like more details on this solution or have any other questions?

Here are five related questions for further exploration:
1. What happens to \( y \) as \( x \) increases?
2. How would you solve for \( x \) instead of \( y \) in this equation?
3. Can you rewrite the equation if \( x = 2 \) and solve for \( y \)?
4. What would the equation look like if the coefficient of \( y \) was different?
5. How would you check if a given pair \((x, y)\) satisfies the equation for a specific \( a \)?

**Tip:** Always factor common terms when solving for a variable, as it simplifies the equation significantly.

Learn how to solve the equation a = 9y + 3yx by factoring and isolating y. This algebra problem covers key concepts like factoring and linear equations. Suitable for students in Grades 8-10.

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